多个ESP8266订阅一个RPI 3

Question

我很难将2(或更多) ESP8266订阅到一个RPi3代理。我用：

import paho.mqtt.client as mqtt
import datetime

mqtt_topics = ["esp8266-1", "esp8266-2"]

def on_connect(client, userdata, flags, rc):
    print("Connected with result code "+str(rc))

    for topic in mqtt_topics:
     client.subscribe(topic)

def on_message(client, userdata, msg):
    print(datetime.datetime.now())
        print(str(msg.topic)+" "+str(msg.payload))

client = mqtt.Client()
client.on_connect = on_connect
client.connect('localhost', 1883, 60)

try:
    for topic in mqtt_topics:
        client.on_message = on_message
    client.loop_forever()
except KeyboardInterrupt:
        print("CTRL-C: Terminating program.")

它只起作用，尤其是1倍。如果我连接even 8266-1，它检查它的值，那么我将even 8266-2连接到它的值，并且even 8266-1不再可用(即使我转到even 8266-2)。

如何同时订阅两个esp8266？我只能在同一时间吃其中一个。

Answer 1

代码几乎不需要修改：

import paho.mqtt.client as mqtt
import datetime

mqtt_topics = [("esp8266-1",0), ("esp8266-2",0)]

def on_connect(client, userdata, flags, rc):
  print("Connected with result code "+str(rc))
  client.subscribe(mqtt_topics)

def on_message(client, userdata, msg):
  print(datetime.datetime.now())
  print(str(msg.topic)+" "+str(msg.payload))

client = mqtt.Client()
client.on_connect = on_connect
client.on_message = on_message
client.connect('localhost', 1883, 60)

try:
  client.loop_forever()
except KeyboardInterrupt:
  print("CTRL-C: Terminating program.")

但是，如果一个客户端工作，而另一个客户端强制第一个客户端断开连接，那么听起来您对两个客户端都有相同的clientID。客户端to需要对所有客户端都是唯一的。