我使用Puppeteer-Sharp下载站点的html,我创建了一个名为GetHtml的方法,它返回包含站点内容的字符串。问题是当我调用行await new BrowserFetcher().DownloadAsync(BrowserFetcher.DefaultRevision);时
应用程序退出时没有任何错误,这是我的代码:
public class Program
{
public static void Main(string[] args)
{
try
{
new FixtureController().AddUpdateFixtures();
}
catch (Exception ex)
{
new Logger().Error(ex);
}
}
}
public async Task AddFixtures()
{
int monthDays = DateTime.DaysInMonth(DateTime.Now.Year, DateTime.Now.Month);
var days = Enumerable.Range(1, monthDays).Select(x => x.ToString("D2")).ToArray();
HtmlDocument doc = new HtmlDocument(); //this is part of Htmlagilitypack library
foreach (var day in days)
{
//Generate url for this iteration
Uri url = new Uri("somesite/" + day);
var html = await NetworkHelper.GetHtml(url);
doc.LoadHtml(html);
}
}因此,每次foreach迭代都将生成一个下载数据的url,方法GetHtml应该返回html,但是当到达var html = ..时,应用程序退出(没有错误),这是GetHtml的代码。
public static async Task<string> GetHtml(Uri url)
{
try
{
//here the crash
await new BrowserFetcher().DownloadAsync(BrowserFetcher.DefaultRevision);
}
catch (Exception e)
{
//No breakpoint point firing
}
await new BrowserFetcher().DownloadAsync(BrowserFetcher.DefaultRevision);
var browser = await Puppeteer.LaunchAsync(new LaunchOptions
{
Headless = true
});
using (Page page = await browser.NewPageAsync())
{
await page.GoToAsync(url.ToString());
return await page.GetContentAsync();
}
}发布于 2018-07-26 12:31:51
您的主方法不等待异步调用的结果。主方法退出,关闭应用程序。要修复它,您需要等待异步方法完成。
如果使用的是C# 7.1或更高版本,则可以使用异步Main:
public class Program
{
public static async void Main()
{
await TestAsync();
}
private static async Task TestAsync()
{
await Task.Delay(5000);
}
}否则,您需要同步等待:
public class Program
{
public static void Main()
{
TestAsync().GetAwaiter().GetResult();
}
private static async Task TestAsync()
{
await Task.Delay(5000);
}
}https://stackoverflow.com/questions/51538808
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