如何通过DFC代码获得当前版本的标签号？

Question

public static IDfCollection getVersions() {
    IDfQuery query = clientX.getQuery();// obtain an idfObject
    query.setDQL(
            "select r_object_id,object_name,r_version_label,owner_name from dm_document(all) where i_chronicle_id='090008868006d5be'");
    IDfCollection collection = null;
    try {
        collection = query.execute(SessionFile.getSession(), IDfQuery.DF_READ_QUERY);
    } catch (DfException e) {
        e.printStackTrace();
    }
    return collection;

}

public class Versions {
public static void main(String[] args) {
    IDfCollection collection = AllOperations.getVersions();
    try {
        int versionsCount = collection.getValueCount("r_object_id");
        //IDfSysObject dfSysObject=(IDfSysObject) SessionFile.getSession().getObject(new DfId("09000886800a143e"));
        while (collection.next()) {
            //String versionNum = dfSysObject.getVersionLabels().getImplicitVersionLabel();
            int i = 0;
            while (i < versionsCount) {
                System.out.println(collection.getRepeatingValue("r_version_label", i));
                i++;
            }
        }
    } catch (DfException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

}

上述代码的输出为: 1.0、1.1、1.2，当前

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代替“当前”标签，我想要“获得版本号”，如2.0或3.0等，这是最新的文档版本号。

所需产出如下：

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Answer 1

首先，这一行：

int versionsCount = collection.getValueCount("r_object_id");

应该是

int versionsCount = collection.getValueCount("r_version_label");

并且必须在while(collection.next())循环中，这样才能正确地迭代所有r_version_label值，因此代码现在将输出：

1.0
1.1
1.2 
CURRENT
2.0

您现在可以摆脱当前(或者，一般情况下，去掉不能解析为浮点数的所有非值)。

Answer 2

IDfDocument doc = (IDfDocument) session.getObject(colDocuments.getId("r_object_id")); 
String versionLabel = doc.getAllRepeatingStrings("r_version_label", null);