首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >如何在MySQL中将行数据转换为列

如何在MySQL中将行数据转换为列
EN

Stack Overflow用户
提问于 2018-07-23 03:14:41
回答 1查看 159关注 0票数 0

第一个问题

我运行这个简单的代码将行数据转换成列,但它只显示第一个数据。为什么会发生这种事?

代码语言:javascript
复制
SELECT  
id_material,    
at_part_number,    
mat_desc,   
GROUP_CONCAT(equipment_name SEPARATOR ', ') As Equipment`

FROM material 

INNER JOIN equipment_list ON material.id_material=equipment_list.PKid_material           
INNER JOIN equipment ON equipment_list.PKid_equipment=equipment.id_equipment;

然后我如何使设备1,设备2,Equipmnet 3,.列?不是用分隔符,而是做一些新的列?

代码语言:javascript
复制
--------------------------------------------------+    
| id_material | mat_part_number | Equipment    
+----------------------------------------------------+   
|     1000001 | AA111           | eq1, eq2, eq3 |  
+-----------------------------------------------------+   

第二个问题

代码语言:javascript
复制
SELECT  
id_material,    
mat_part_number,   
mat_desc,`   
GROUP_CONCAT(equipment_name SEPARATOR ', ') As Equipment

FROM material 

INNER JOIN equipment_list ON material.id_material=equipment_list.PKid_material INNER JOIN equipment ON equipment_list.PKid_equipment=equipment.id_equipment;

UNION

SELECT  
id_material,    
alt_part_number,   
mat_desc,   
GROUP_CONCAT(equipment_name SEPARATOR ', ') As Equipment 

FROM material 

INNER JOIN equipment_list ON material.id_material=equipment_list.PKid_material    
INNER JOIN equipment ON equipment_list.PKid_equipment=equipment.id_equipment      
INNER JOIN alternatif_list ONmaterial.id_material=alternatif_list.PKid_material    
INNER JOIN alternatif ON alternatif.id_alternatif=alternatif_list.PKid_alternatif

ORDER BY
id_material asc;

注:材料是母表,材料表和设备表有多对多的关系,所以材料表和备用表。1种材料可以包括2种设备,2种交替(材料的设备等于交替的设备)

我想做这个

代码语言:javascript
复制
`---------------------------------------------------------------------------`   
`id_material | part_number | equipment (1) | equipment (2) | equipment (n) |`     
`---------------------------------------------------------------------------`  
`100001 | AA111 | nameeq1 |nameeq2 |`    
`100001 | AA112 | nameeq1 |nameeq2 |`    //alternatif part_number    
`100002 | AA222 | nameeq3 |    |`    
`100002 | AA221 | nameeq3 |    |`      //alternatif part_number       
`100003 | AA333 | nameeq4 |nameeq5    |`          
`100003 | AA331 | nameeq4 |nameeq5    |`     //alternatif part_number   
EN

回答 1

Stack Overflow用户

发布于 2018-07-23 06:19:29

考虑到这么简单的数据

代码语言:javascript
复制
DROP TABLE IF EXISTS T;
CREATE TABLE T (ID INT,col1 varchar(3));

insert into t values (1,'aaa'),(1,'bbb'),(2,'aaa'),(3,'aaa'),(3,'bbb'),(3,'ccc');

如果你group_concat没有一个组

代码语言:javascript
复制
select id,group_concat(col1)
from t;

你明白了

代码语言:javascript
复制
+------+-------------------------+
| id   | group_concat(col1)      |
+------+-------------------------+
|    1 | aaa,bbb,aaa,aaa,bbb,ccc |
+------+-------------------------+
1 row in set (0.00 sec)

与组

代码语言:javascript
复制
select id,group_concat(col1)
from t
group by id;

你明白了

代码语言:javascript
复制
+------+--------------------+
| id   | group_concat(col1) |
+------+--------------------+
|    1 | aaa,bbb            |
|    2 | aaa                |
|    3 | aaa,bbb,ccc        |
+------+--------------------+
3 rows in set (0.00 sec)

如果您想要单独的列,并且有已知的有限数量的值,可以使用条件聚合。

代码语言:javascript
复制
select id,
         max(case when col1 = 'aaa' then col1 else '' end) as first,
         max(case when col1 = 'bbb' then col1 else '' end) as second,
         max(case when col1 = 'ccc' then col1 else '' end) as third
from t
group by id;

为了得到这个

代码语言:javascript
复制
+------+-------+--------+-------+
| id   | first | second | third |
+------+-------+--------+-------+
|    1 | aaa   | bbb    |       |
|    2 | aaa   |        |       |
|    3 | aaa   | bbb    | ccc   |
+------+-------+--------+-------+
3 rows in set (0.00 sec)

如果您不知道这些值,或者它们可能会更改,那么您可以构建一个sql语句并将其提交给动态sql。

代码语言:javascript
复制
set @sql = (
    select group_concat(concat('max(case when col1 = ', char(39),s.val,char(39),' then col1 else null end) as ', val))
    from
    (select distinct col1 as val from t order by col1) s
    )
;
set @sql = concat('select id,', @sql,' from t group by id;');   
prepare sqlstmt from @sql;
execute sqlstmt;
deallocate prepare sqlstmt;

返回以下内容

代码语言:javascript
复制
+------+------+------+------+
| id   | aaa  | bbb  | ccc  |
+------+------+------+------+
|    1 | aaa  | bbb  | NULL |
|    2 | aaa  | NULL | NULL |
|    3 | aaa  | bbb  | ccc  |
+------+------+------+------+
3 rows in set (0.00 sec)

如果您想限制列的数量,那么使用一个变量来计算最大列数,如下所示

代码语言:javascript
复制
DROP TABLE IF EXISTS T;
CREATE TABLE T (ID INT,col1 varchar(3));

insert into t values (1,'aaa'),(1,'bbb'),(2,'aaa'),(3,'aaa'),(3,'ddd'),(3,'eee');


set @sql = (
    select group_concat(distinct concat('max(case when s.rn = ', S.RN,' then col1 else null end) as Equipment_', S.RN))
    from
    (
        SELECT ID,
             IF(ID <> @P, @RN:=1,@RN:=@RN+1) RN,
            @P:=ID P
        FROM T
        CROSS JOIN (SELECT @RN:=0,@P:=0) R
    ) S
    );

set @sql = concat('select id,', @sql,' from 
(
        SELECT ID,col1,
             IF(ID <> @P, @RN:=1,@RN:=@RN+1) RN,
            @P:=ID P
        FROM T
        CROSS JOIN (SELECT @RN:=0,@P:=0) R
        order by id,col1
) S group by id;'); 

#SELECT @SQL;

prepare sqlstmt from @sql;
execute sqlstmt;
deallocate prepare sqlstmt;

+------+-------------+-------------+-------------+
| id   | Equipment_1 | Equipment_2 | Equipment_3 |
+------+-------------+-------------+-------------+
|    1 | aaa         | bbb         | NULL        |
|    2 | aaa         | NULL        | NULL        |
|    3 | aaa         | ddd         | eee         |
+------+-------------+-------------+-------------+
3 rows in set (0.00 sec)
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/51471163

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档