设置Lua脚本的要求搜索路径

Question

我试图从一个Lua脚本中使用require，这个脚本是我使用luaL_loadstring加载的。

这是我的密码：

lua_State *L = luaL_newstate();
luaL_openlibs(L);
lua_settop(L, 0);
const char *script = "require('test.lua')";
const int ret = luaL_loadstring(L, script);
if (ret || lua_pcall(L, 0, LUA_MULTRET, 0))
{
    std::cout << "Error: " << lua_tostring(L, -1) << std::endl;
}
lua_close(L);

但是，当我运行代码时，我会得到以下错误。

Error: [string "require('test.lua')"]:1: module 'test.lua' not found:
no field package.preload['test.lua']
no file '/usr/local/share/lua/5.3/test/lua.lua'
no file '/usr/local/share/lua/5.3/test/lua/init.lua'
no file '/usr/local/lib/lua/5.3/test/lua.lua'
no file '/usr/local/lib/lua/5.3/test/lua/init.lua'
no file './test/lua.lua'
no file './test/lua/init.lua'
no file '/usr/local/lib/lua/5.3/test/lua.so'
no file '/usr/local/lib/lua/5.3/loadall.so'
no file './test/lua.so'
no file '/usr/local/lib/lua/5.3/test.so'
no file '/usr/local/lib/lua/5.3/loadall.so'
no file './test.so'

是否可以为Lua脚本设置搜索路径，以便我可以使用相对路径使用require？

Answer 1

多亏了@Henri_Menke，我可以使用下面的代码来工作。

/* set the current working directory */
const char *currentDir = "directory/to/script";
chdir(currentDir);
/* init lua and run script */
lua_State *L = luaL_newstate();
luaL_openlibs(L);
lua_settop(L, 0);
const char *script = "require('test')";
const int ret = luaL_loadstring(L, script);
if (ret || lua_pcall(L, 0, LUA_MULTRET, 0))
{
    std::cout << "Error: " << lua_tostring(L, -1) << std::endl;
}
lua_close(L);