我知道怎么做对案件不敏感的搜索。
例子:
aaa@aaa.com但是:AAA@aaa.com
db.getCollection('members').aggregate( {$lookup:{‘来自’用户‘,'localField':'members.email','foreignField':'email','as':'users'}},{$unwind:{path:'$users',preserveNullAndEmptyArrays: true}},{$match:{$match:{ $exists: false }} );集合成员看起来如下:
{
"_id" : ObjectId("5b439c02a5439e00568291fe"),
"members" : [
{
"email" : "aaa@gmail.com"
},
{
"email" : "bbb@gmail.com"
},
{
"email" : "ccc@gmail.com"
}
],
"groupname" : "abuse",
"active" : true,
"createdAt" : ISODate("2018-07-09T17:31:46.098Z"),
"updatedAt" : ISODate("2018-07-09T17:31:46.098Z"),
"__v" : 0
}集合member_user如下所示:
{
"_id" : ObjectId("5a7dfce545e13f0233b2e451"),
"email" : "AAA@gmail.com",
"__v" : 0
}
{
"_id" : ObjectId("5b43ac89bfd90aa9cc4a68c2"),
"email" : "bbb@gmail.com",
"__v" : 0
}这是我使用的代码:
db.getCollection('member').aggregate([
{$unwind: "$members"},
{$lookup: {'from': 'member_user', 'localField': 'members.email', 'foreignField': 'email', 'as': 'users'}},
{$unwind: {path: '$users', preserveNullAndEmptyArrays: true}},
{$match : { users: { $exists: false } }},
],
{
collation: {
locale: 'en_US',
strength: 1
}
}
);当数据集很小时,速度总是非常快。但我有24K会员和7K用户。正如我所说的,当{$match:{ $exists: true }}时,速度是可以的,但是当{$match:{$match:{ $exists: false }}时,速度几乎是60倍。(1秒vs 1分钟)
没有校对,速度总是快的。
发布于 2018-07-10 02:38:25
您需要使用localField聚合将foreignField和$toLower转换为小写,这样就可以轻松地匹配字段。
db.collection.aggregate([
{ "$unwind": "$members" },
{ "$addFields": { "members.email": { "$toLower": "$members.email" }}},
{ "$lookup": {
"from": "users",
"let": { "membersEmail": "$members.email" },
"pipeline": [
{ "$addFields": { "email": { "$toLower": "$email" }}},
{ "$match": { "$expr": { "$eq": [ "$email", "$$membersEmail" ] } } }
],
"as": "members.email"
}},
{ "$unwind": "$members.email" },
{ "$group": {
"_id": "$_id",
"groupname": { "$first": "$groupname" },
"active": { "$first": "$active" },
"members": { "$push": "$members.email" }
}}
])https://stackoverflow.com/questions/51249218
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