Django viewflow扩展任务视图

Question

我正在尝试一个在应用程序中同时使用django-视图流和django-许可的想法，在应用程序中会有一些复杂的权限规则。我理解django-许可权工作方式的方法是在要应用权限规则的视图中添加一个装饰器。

通过扩展基本视图流视图并将urls.py指向扩展视图，我成功地实现了对流程视图的处理。当我试图对任务遵循相同的想法时，我会遇到下面列出的错误

类型对象'CBVTask‘没有属性'flow_class’

models.py

class CBVArticle(models.Model):
    created_by = models.ForeignKey(User)
    title = models.CharField(max_length=100)
    content = models.TextField()

class CBVArticleProcess(Process):
    article = models.ForeignKey(CBVArticle, blank=True, null=True)

class CBVTask(Task):

    class Meta:
        proxy = True

flow.py

class CBVArticleFlow(Flow):
    process_class = models.CBVArticleProcess
    task_class = models.CBVTask

    start = (
        flow.Start(views.ArticleCreate).Next(this.end)
    )

    end =flow.End()

urls.py

myflow_urls = FlowViewSet(CBVArticleFlow).urls  

urlpatterns = [
    url(r'^process/(?P<process_pk>\d+)/$', views.TestDetailProcessView.as_view(), kwargs = dict(flow_class=CBVArticleFlow), name='detail'),
    url(r'^process/(?P<process_pk>\d+)/start/(?P<task_pk>\d+)/detail/$', views.DetailTaskView.as_view(), kwargs = dict(flow_class=CBVArticleFlow, flow_task=CBVTask), name='start__detail'),
]

views.py

from viewflow.flow.views import DetailProcessView as BaseDetailProcessView, DetailTaskView as BaseDetailTaskView

@permission_required('test_app_cbv.view_cbvarticleprocess')
class TestDetailProcessView(BaseDetailProcessView):
    template_name = 'test_app_cbv/detail.html'

    def get_queryset(self):
        pk = self.kwargs['process_pk']

        return models.CBVArticleProcess.objects.filter(process_ptr_id = pk)

class DetailTaskView(BaseDetailTaskView):
    template_name = 'test_app_cbv/task_detail.html'

提前感谢您的指点！

Answer 1

结果是一个菜鸟的错误-- urls.py文件应该是这样读的：

urls.py

myflow_urls = FlowViewSet(CBVArticleFlow).urls  

urlpatterns = [
    url(r'^process/(?P<process_pk>\d+)/$', views.TestDetailProcessView.as_view(), kwargs = dict(flow_class=CBVArticleFlow), name='detail'),
    url(r'^process/(?P<process_pk>\d+)/start/(?P<task_pk>\d+)/detail/$', views.DetailTaskView.as_view(), kwargs = dict(flow_class=CBVArticleFlow, flow_task=CBVArticleFlow.start), name='start__detail'),
]