我在See.if()中遇到了一个问题,它有时会返回空字符串。
使用的技术堆栈:
以下是错误:断言错误:期望“”包含“操作成功”
steps.ts
this.Then(/^he should see the user (.*) success message$/, (severity) => {
browser.waitForAngularEnabled(false); // Workaround fix for p-growl
return stage.theActorInTheSpotlight().attemptsTo(
Messages.called(severity)
);
});Task.ts
import { PerformsTasks, Task, Enter, Click, See, Is, Wait, Text } from 'serenity-js/protractor';
import { expect } from '../utils/expect';
import { ListUI } from '../components/ui';
export class Messages implements Task {
constructor(private severity: string) { }
static called(severity: string) {
return new Messages(severity);
}
performAs(actor: PerformsTasks): PromiseLike<void> {
if (this.severity.toLowerCase() === 'success') {
return actor.attemptsTo(
Wait.until(ListUI.message, Is.present()),
See.if(
Text.of(ListUI.message),
actual => expect(actual).to.eventually.include('Operation Success')
),
Click.on(ListUI.messageCloseWidget)
);
}
}
}ui.ts
import { Target, Text } from 'serenity-js/protractor';
import { by } from 'protractor';
export class ListUI {
static message = Target.the('Message Widget')
.located(by.id('messages'));
static messageCloseWidget = Target.the('Message Close Widget')
.located(by.css('#messages .ui-growl-icon-close'));
}请帮帮我。提前谢谢。
发布于 2018-07-06 14:14:04
尝试使用Wait.for(Duration.ofSeconds(5)),在wait.until()之前
Wait.for(Duration.ofSeconds(5)),
Wait.until(ListUI.message, Is.present()),发布于 2018-07-16 12:36:25
我通过提供原始咆哮信息选择器来解决这个问题。
为消息提供准确的选择器(#messages ..ui咆哮-消息)。
以下代码是固定的:
import { Target, Text } from 'serenity-js/protractor';
import { by } from 'protractor';
export class ListUI {
static message = Target.the('Message Widget')
.located(by.css('#messages .ui-growl-message'));
static messageCloseWidget = Target.the('Message Close Widget')
.located(by.css('#messages .ui-growl-icon-close'));
}https://stackoverflow.com/questions/51211294
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