语音控制音乐系统，如何选择音乐？

Question

我正在创建一个声音控制的音乐系统。我现在的系统工作得很好，但做得很差。它把单词拆开，看音乐选集。但是，如果有些歌曲的标题与我说的相同(就像我说的"of“，它找到了5首歌)，它会选择音乐列表中的最后一首歌。有人知道更好的选择音乐的方法吗？

def detectWords(response):
    response = response.lower()
    words = response.split()

    if 'play' in words:
            os.chdir("/home/pi/Desktop/Stemherkenning/Music")
            for file in glob.glob("*mp3"):
                fileSplit = (file.lower()).split()
                if any(word in fileSplit for word in words):
                    mixer.music.load(file)
                    mixer.music.play()
                    print("Playing " + file) 

    if 'stop' in words:
        print("Stopped")
        mixer.music.stop()

“单词”是谷歌语音识别所使用的词汇。

Answer 1

有多种方法来处理这个问题，有不同程度的复杂。此方法检查与上述短语有最独特的单词的歌曲，它将帮助您开始：

import os
import glob
import mixer
import operator

def title_match(title, songlist):
    """Returns the song from `songlist` whose title has 
    the most unique words in common with `title`.
    If two such songs have the same amount of words intersecting, 
    only returns one song."""

    title = set(tuple(title))
    matches = {song: len(title & set(song.lower().split())) for song in songlist}
    result = max(matches.items(), key=operator.itemgetter(1))[0]

    return result


def detectWords(response):
    response = response.lower()
    words = response.split()

    if 'play' in words:
        os.chdir("/home/pi/Desktop/Stemherkenning/Music")
        songlist = [file for file in glob.glob("*mp3")]
        title = words[words.index("play")+1:]
        file = title_match(title, songlist) #grabs closest matching file
        print("Playing: " + file)
        mixer.music.load(file)
        mixer.music.play()

    if 'stop' in words:
        print("Stopped")
        mixer.music.stop()