将光标隐藏在静止的时间内，并在移动时再次显示。

Question

我想在一定时间后隐藏光标(如果鼠标没有移动)，当我在picturebox中移动鼠标时，我想显示光标。我就是不能让它起作用..。这就是我尝试过的：

    // this Never seem to hide the cursor
    private void picBox_MouseMove(object sender, MouseEventArgs e)
    {
        Cursor.Show();
        tim.Stop();
        tim.Start();
    }
    private void tim_Tick(object sender, EventArgs e)
    {
        Cursor.Hide();
        tim.Stop();
    }

-

    // works but in this case I want cursor.ico to be a resource
    private void picBox_MouseMove(object sender, MouseEventArgs e)
    {
        Cursor.Current = Cursors.Default;
        tim.Stop();
        tim.Start();
    }
    private void tim_Tick(object sender, EventArgs e)
    {
        Cursor.Current = new Cursor("cursor.ico");
        tim.Stop();
    }

-

    // Properties.Resources.cursor gives an error even though I added it to my resources
    // cannot convert from 'System.Drawing.Icon' to 'System.IntPtr'
    private void picBox_MouseMove(object sender, MouseEventArgs e)
    {
        Cursor.Current = Cursors.Default;
        tim.Stop();
        tim.Start();
    }
    private void tim_Tick(object sender, EventArgs e)
    {
        Cursor.Current = new Cursor(Properties.Resources.cursor);
        tim.Stop();
    }

Answer 1

您需要有一个定时器并处理它的Tick事件。在Tick事件中，检查鼠标的最后一次移动是否在特定时间之前，然后使用Cursor.Hide()隐藏光标。还可以处理MouseMove的PictureBox，并使用Cursor.Show()方法显示光标。

注意:不要忘记启用计时器并将计时器的Interval设置为短值，例如，在以下代码中更改300和更改duration值，以缩短/较长的非活动时间：

DateTime? lastMovement;
bool hidden = false;
int duration = 2;
void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
    lastMovement = DateTime.Now;
    if (hidden)
    {
        Cursor.Show();
        hidden = false;
    }
}
private void timer1_Tick(object sender, EventArgs e)
{
    if (!lastMovement.HasValue)
        return;
    TimeSpan elaped = DateTime.Now - lastMovement.Value;
    if (elaped >= TimeSpan.FromSeconds(duration) && !hidden)
    {
        Cursor.Hide();
        hidden = true;
    }
}