用加密加密Arraybuffer

Question

我尝试用AES加密ArrayBuffer，因此将其转换为wordArray，然后转换为字符串：

private encrypt(file: ArrayBuffer, key: string): string {
    const wordArray = CryptoJS.lib.WordArray.create(file);
    const str = CryptoJS.enc.Hex.stringify(wordArray);
    console.log(str); //6920616d206120737472696e67
    return CryptoJS.AES.encrypt(str, key).toString();
}

现在我想解密回一个ArrayButter，但是打印的字符串甚至不匹配：

private decrypt(file: string, key: string) {
    const decrypted = CryptoJS.AES.decrypt(file, key);
    console.log(decrypted.toString()); //3639323036313664323036313230373337343732363936653637
}

我想我搞砸了一些步骤，但我不知道在哪里。

更新:我需要将字符串转换为utf以生成一个wordarray：

private decrypt(file: string, key: string) {
    const decrypted = CryptoJS.AES.decrypt(file, key);
    const str = decrypted.toString(CryptoJS.enc.Utf8);
    const wordArray = CryptoJS.enc.Hex.parse(str);
}

现在，我离再次将它转换为ArrayBuffer只差一步了

Answer 1

function CryptJsWordArrayToUint8Array(wordArray) {
  const l = wordArray.sigBytes;
  const words = wordArray.words;
  const result = new Uint8Array(l);
  var i = 0 /*dst*/, j = 0 /*src*/;
  while (true) {
    // here i is a multiple of 4
    if (i == l) {
      break;
    }
    var w = words[j++];
    result[i++] = (w & 0xff000000) >>> 24;
    if (i == l) {
      break;
    }
    result[i++] = (w & 0x00ff0000) >>> 16;
    if (i == l) {
      break;
    }
    result[i++] = (w & 0x0000ff00) >>> 8;
    if (i == l) {
      break;
    }
    result[i++] = (w & 0x000000ff);
  }
  return result;
}