如何输出自定义while循环php

Question

我想在while循环中使用一个计数器作为自定义，假设我们有一个while循环< 21，我试图输出类似这样的结果：

1,2,
3,4,
5,6,7,
8,9,
10,11,
12,13,14,
15,16,
17,18,
19,20,21

我试着写这些代码

<?php 

$counter = 1;

while ($counter <21) : 
    if( $counter == 1 || ($counter-1)%4 == 0 ) { 
        echo $counter."<br>";
    } 

    if( $counter == 2 || ($counter-2)%4 == 0 ) { ?>
    <div class="others">
    <?php } 
    if( $counter != 1 && ($counter-1)%4 != 0 ) { 
        echo $counter.',';
    }
    if( $counter%4 == 0 ) { ?>
        </div>
    <?php } 
    $counter++;
endwhile; 

但是输出是这样的

1
2,3,4,
5
6,7,8,
9
10,11,12,
13
14,15,16,
17
18,19,20,

解决了

@cannon给出了一个完美的解决方案，但是我希望使用循环来调用数据库posts，所以我解决了这个问题.

<?php
$counter = 1;
$module =  7;
$i = 2;
$arr = [];
while ($counter <22) : 
    if( $counter == 1 || ($counter-1)% $module == 0  ) { 
        echo $counter.',';
    } 
    if(  $counter == 2  || ($counter-2)% $module    == 0 ) { 
        echo $counter.',<br>';
    } 
    if( $counter == 3 || ($counter-3)% $module == 0  ) { 
        echo $counter.',';
    } 
    if(  $counter == 4  || ($counter-4)% $module    == 0 ) { 
        echo $counter.',<br>';
    }
    $i = $i + $module;
    $arr[] = $i;
    if(!in_array($counter,$arr)){
        if( $counter == 5 || ($counter-5)% $module == 0 ) { 
            } 
        if( $counter != 1 && $counter != 2  && $counter != 3 && ($counter-1)% $module != 0  
        && $counter != 4  && ($counter-3)% $module != 0 && ($counter-4)% $module != 0  ) { 
            echo $counter.',';
        }
        if( $counter% $module == 0 ) { 
            echo '<br>';
        }
    } 
    $counter++;
endwhile; 

Answer 1

您可以尝试这样的方法，它应该像您所描述的那样起作用：

$counter = 1;
for($i = 1; $i < 21; $i++){
    echo $i . ',';

    if($counter % 6 == 0){
        echo ++$i . ',<br>';
    }
    elseif($counter % 2 == 0){
        echo '<br>';
    }
    $counter++;
}