码头组合，不能在码头集装箱中打印环境变量

Question

我想打印环境变量定义在坞-撰写文件。

这是我的docker-compose-1.yml

version: '3.6'

services:
  busybox:
    image: busybox
    command: 'echo $DEBUG'
    environment:
      - DEBUG='123456'

并且，尝试在docker容器中打印DEBUG环境变量：

☁  environment-variables-in-compose [master] ⚡  docker-compose -f docker-compose-1.yml up
WARNING: The DEBUG variable is not set. Defaulting to a blank string.
Creating network "environmentvariablesincompose_default" with the default driver
Creating environmentvariablesincompose_busybox_1 ... done
Attaching to environmentvariablesincompose_busybox_1
busybox_1  |
environmentvariablesincompose_busybox_1 exited with code 0

如你所见，有WARNING: The DEBUG variable is not set. Defaulting to a blank string.

我说错了吗？

更新1:

docker-compose-1.yml

version: '3.6'

services:
  busybox:
    image: busybox
    command: 'echo $$DEBUG'
    environment:
      DEBUG: 123456

我使用双command符号更改$，但结果仍然不是我想要的。

☁  environment-variables-in-compose [master] ⚡  docker-compose -f docker-compose-1.yml up
Creating network "environmentvariablesincompose_default" with the default driver
Creating environmentvariablesincompose_busybox_1 ... done
Attaching to environmentvariablesincompose_busybox_1
busybox_1  | $DEBUG
environmentvariablesincompose_busybox_1 exited with code 0

如您所见，环境变量被打印为$DEBUG，而不是期望值123456。

Answer 1

撰写将从您运行撰写的环境中展开变数。若要在容器中展开变量，请使用$使用$$转义

command: '/bin/sh -c "echo $$DEBUG"'

有关更多详细信息，请参见：https://docs.docker.com/compose/compose-file/#variable-substitution

编辑:我还在容器中添加了一个shell来展开变量。