我在ModelMapper框架上遇到了麻烦。请解释一下为什么我看到下面的行为。
在build.gradle中有一个下面的依赖项
compile group: 'org.modelmapper', name: 'modelmapper', version: '2.0.0'还有一位顾客:
public class Customer {
private String name;
private int age;
public Customer() {
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public String toString() {
return MoreObjects.toStringHelper(this)
.add("name", name)
.add("age", age)
.toString();
}
}我还有个地图:
public class CustomerPropertyMap extends PropertyMap<Customer, Customer> {
private final Condition<String, String> isFred = s -> isFred(s.getSource());
@Override
protected void configure() {
when(isFred).map(source.getName()).setName("George");
map(source.getAge(), destination.getAge());
}
boolean isFred(String s) {
return "Fred".equals(s);
}
}和一次考验
public class PropertyMapTest {
CustomerPropertyMap customerPropertyMap = new CustomerPropertyMap();
ModelMapper modelMapper = new ModelMapper();
@Before
public void init() {
modelMapper.addMappings(customerPropertyMap);
}
@Test
public void fred() {
Customer customer = new Customer();
customer.setAge(40);
customer.setName("Fred");
Customer mapped = modelMapper.map(customer, Customer.class);
System.out.println(mapped);
}
@Test
public void nonFred() {
Customer customer = new Customer();
customer.setAge(40);
customer.setName("Qwerty");
Customer mapped = modelMapper.map(customer, Customer.class);
System.out.println(mapped);
}
}在fred()方法输出中,nonFred("Customer{name=null,age=40}")中的“Customer{name=null,age=40}”是“Customer{name=null,age=40}”。你能解释一下为什么吗?为什么我没有在第一种方法中看到输出"George“?
发布于 2018-06-23 18:15:51
当用于在源类型和目标类型之间的条件映射时
在您的情况下,只有在满足条件“Fred”.equals(名称)时才映射名称。
https://stackoverflow.com/questions/50972990
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