我有两张桌子,即。产品和机构。在机构和产品中都有一个主键pid自动递增,一个id是32长度的varchar。
每个product都需要引用它的institution,因此我在products中设置institution列,并希望它是引用机构的id的外键。
然而,我一直在犯这个错误,我花了一整晚的时间试图弄清楚这个错误,但没有成功。
$ php artisan migrate
Migration table created successfully.
Illuminate\Database\QueryException : SQLSTATE[HY000]: General error: 1005 Can't create table `devbase`.`#sql-824_f23` (errno: 150 "Foreign key constraint is incorrectly formed") (SQL: alter table `institutions` add constraint `institutions_id_foreign` foreign key (`id`) references `institution` (`products`) on delete RESTRICT)
at [...]\vendor\laravel\framework\src\Illuminate\Database\Connection.php:664
660| // If an exception occurs when attempting to run a query, we'll format the error
661| // message to include the bindings with SQL, which will make this exception a
662| // lot more helpful to the developer instead of just the database's errors.
663| catch (Exception $e) {
> 664| throw new QueryException(
665| $query, $this->prepareBindings($bindings), $e
666| );
667| }
668|
Exception trace:
1 PDOException::("SQLSTATE[HY000]: General error: 1005 Can't create table `devbase`.`#sql-824_f23` (errno: 150 "Foreign key constraint is incorrectly formed")")
[...]\vendor\laravel\framework\src\Illuminate\Database\Connection.php:458
2 PDOStatement::execute()
[...]\vendor\laravel\framework\src\Illuminate\Database\Connection.php:458
Please use the argument -v to see more details.这是对机构表的迁移,文件名是2018_06_14_165449_create_institutions_table.php。
public function up()
{
Schema::create('institutions', function (Blueprint $table) {
$table->increments('pid');
$table->string('id', 32)->unique();
$table->string('shortname', 16)->unique();
$table->text('fullname');
$table->string('logo', 100);
$table->timestamps();
});
}同时,这是对products表的迁移,文件名是2018_06_15_031837_create_products_table.php
public function up()
{
Schema::enableForeignKeyConstraints();
Schema::create('products', function (Blueprint $table) {
$table->increments('pid');
$table->string('id', 32)->unique();
$table->string('url', 100)->unique();
$table->string('shortname', 16)->unique();
$table->string('institution', 32)->index()->nullable();
$table->timestamps();
$table->foreign('institution')
->references('institutions')
->on('id')
->onDelete('RESTRICT');
});
}发布于 2018-06-15 04:35:40
$table->foreign('institution')
->references('id')
->on('institutions')
->onDelete('RESTRICT');希望能帮上忙。
https://stackoverflow.com/questions/50869137
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