python行为不检测步骤文件

Question

我对Python很陌生，行为举止也不错。我正试图为我的自动化项目设置一个POC。我遵循了“行为”文档中的教程，但是当我运行“行为”时，它抛出的步骤是不可检测的。我遗漏了什么？

我的文件夹结构是这样的。

/features/testone.feature
/features/steps/testone_steps.py

特征文件

Feature: Running sample feature

@smoke @regression
Scenario: Login to github and verify it works in testone feature of scenario one
Given Launch GITHUB app with "test@test.com" and "githubtest"

step文件

from behave import given, when, then, step

@given(u'Launch GITHUB app with "{text}" and "{text}"')
def step_impl(context, user, password):
    print(f"This is the given step with {user} and {password}")

输出

λ behave
Feature: Running sample feature # features/testone.feature:1

  @smoke @regression
  Scenario: Login to github and verify it works in testone feature of scenario one  # features/testone.feature:4
    Given Launch GITHUB app with "test@test.com" and "githubtest"                   # None


Failing scenarios:
  features/testone.feature:4  Login to github and verify it works in testone feature of scenario one

0 features passed, 1 failed, 0 skipped
0 scenarios passed, 1 failed, 0 skipped
0 steps passed, 0 failed, 0 skipped, 1 undefined
Took 0m0.000s

You can implement step definitions for undefined steps with these snippets:

@given(u'Launch GITHUB app with "test@test.com" and "githubtest"')
def step_impl(context):
    raise NotImplementedError(u'STEP: Given Launch GITHUB app with "test@test.com" and "githubtest"')

我在vscode编辑器中注意到，在steps文件中，pylint显示了以下消息。

[pylint] E0611:No name 'given' in module 'behave'
[pylint] E0611:No name 'when' in module 'behave'
[pylint] E0611:No name 'then' in module 'behave'
[pylint] E0611:No name 'step' in module 'behave'

Answer 1

您的问题是在step文件中使用了不正确的格式。试试这个：

from behave import given, when, then, step

@given(u'Launch GITHUB app with "{user}" and "{password}"')
def step_impl(context, user, password):
    print("This is the given step with {user} and {password}".format(user, password))

注意，@given语句中定义的参数与step_impl()中传递的参数匹配。

也就是说，如果在@given中，您有

@given(u'Launch GITHUB app with "{user}" and "{password}"')

那么在您的步骤实现中，您应该

def step_impl(context,user,password)

如果没有此匹配，并且在当前代码中，您将收到NotImplementedError，因为parameters正在寻找一个步骤实现，其中的参数是context和text作为步骤文件中的参数，即def step_impl(context, text)。