从循环中生成的字符串中删除最后一个字符

Question

相信我，我已经尝试过堆栈溢出的所有东西了！

所以，我有个JSON -

$j={
    "itempicture": [
        {
            "status": "3"
        },
        {
            "ItemCode": "001",
            "ItemImage": "image1",
            "ItemCategory": "shirt",
            "ShowOnPOS": "Yes",
            "LastModifiedOn": "2018-06-02 11:53:57"
        },
        {
            "ItemCode": "002",
            "ItemImage": "image2",
            "ItemCategory": "shirt",
            "ShowOnPOS": "Yes",
            "LastModifiedOn": "2018-06-02 11:53:57"
        }
    ]
}

我是这样访问它的-

$jo = json_decode($j);
for($i = 1; $i < count($jo->itempicture); $i++) {
    foreach($jo->itempicture[$i] as $prop=>$val) {
        echo $val.",";
    }
    echo '<br>';
}

我得到了这个输出-

001,image1,shirt,Yes,2018-06-02 11:53:57,
002,image2,shirt,Yes,2018-06-02 11:53:57,

这个输出的主要问题是最后的"，“。我无法移除它！

什么都试过了-这个- Remove the last character from string

有底座，里边，内爆.一切！

不管用了！

Answer 1

这是解决办法

$j='{"itempicture":[
{
    "status":"3"
},
{
    "ItemCode":"001",
    "ItemImage":"image1",
    "ItemCategory":"shirt",
    "ShowOnPOS":"Yes",
    "LastModifiedOn":"2018-06-02 11:53:57"
},
{
    "ItemCode":"002",
    "ItemImage":"image2",
    "ItemCategory":"shirt",
    "ShowOnPOS":"Yes",
    "LastModifiedOn":"2018-06-02 11:53:57"
}
]
}';
$jo=json_decode($j);
$edata = '';
for($i=1;$i<count($jo->itempicture);$i++){
    $data = '';
    foreach($jo->itempicture[$i] as $prop=>$val){
        $data .= $val.",";
    }
    $edata .= rtrim($data, ",");
    $edata .='<br/>';
}

echo "<pre>";
print_r($edata);
echo "</pre>";

Answer 2

使用implode()的版本意味着您必须将JSON转换为数组(默认的转换为对象，因此将true作为第二个参数添加到json_decode()中)。

$j='{"itempicture":[
{
    "status":"3"
},
{
    "ItemCode":"001",
    "ItemImage":"image1",
    "ItemCategory":"shirt",
    "ShowOnPOS":"Yes",
    "LastModifiedOn":"2018-06-02 11:53:57"
},
{
    "ItemCode":"002",
    "ItemImage":"image2",
    "ItemCategory":"shirt",
    "ShowOnPOS":"Yes",
    "LastModifiedOn":"2018-06-02 11:53:57"
}
]
}';
$jo=json_decode($j, true);
array_shift($jo['itempicture']);
$edata = '';
foreach ( $jo['itempicture'] as $item)  {
    $edata .= implode(",", $item).'<br/>';
}
echo "<pre>";
print_r($edata);
echo "</pre>";

印出来..。

<pre>001,image1,shirt,Yes,2018-06-02 11:53:57<br/>
002,image2,shirt,Yes,2018-06-02 11:53:57<br/></pre>

Answer 3

你可以做这样的事

 $jo=json_decode($j);

 for($i=1;$i<count($jo->itempicture);$i++){
 foreach($jo->itempicture[$i] as $prop=>$val){
      if ($value === end($jo->itempicture[$i])) {
        echo $val;
      }
      else {
        echo $val.",";
      }
 }
 echo '<br>';
}

这将通过比较当前的迭代是否是循环的结束来防止编写最后的“，”