将字段添加到Graphcool密码模板突变

Question

我使用电子邮件密码模板设置我的图形服务器与用户身份验证。当注册一个新用户时，我想为“name”添加一个属性。我向用户模型添加了名称，并更新了signup.graphql和signup.ts代码，如下所示。

当运行createUser突变时，我会得到一个错误，它说“没有定义名称”。我不知道问题出在哪里。任何帮助都是非常感谢的！

signup.graphql

extend type Mutation {
  signupUser(email: String!, password: String!, name: String): SignupUserPayload
}

signup.ts

interface EventData {
  email: string
  password: string
  name: string
}

const SALT_ROUNDS = 10

export default async (event: FunctionEvent<EventData>) => {
  console.log(event)

  try {
    const graphcool = fromEvent(event)
    const api = graphcool.api('simple/v1')

    const { email, password } = event.data

    if (!validator.isEmail(email)) {
      return { error: 'Not a valid email' }
    }

    // check if user exists already
    const userExists: boolean = await getUser(api, email)
      .then(r => r.User !== null)
    if (userExists) {
      return { error: 'Email already in use' }
    }

    // create password hash
    const salt = bcrypt.genSaltSync(SALT_ROUNDS)
    const hash = await bcrypt.hash(password, salt)

    // create new user
    const userId = await createGraphcoolUser(api, email, hash, name)

    // generate node token for new User node
    const token = await graphcool.generateNodeToken(userId, 'User')

    return { data: { id: userId, token } }
  } catch (e) {
    console.log(e)
    return { error: 'An unexpected error occured during signup.' }
  }
}

async function getUser(api: GraphQLClient, email: string): Promise<{ User }> {
  const query = `
    query getUser($email: String!) {
      User(email: $email) {
        id
      }
    }
  `

  const variables = {
    email,
  }

  return api.request<{ User }>(query, variables)
}

async function createGraphcoolUser(api: GraphQLClient, email: string, password: string, name: string): Promise<string> {
  const mutation = `
    mutation createGraphcoolUser($email: String!, $password: String!, $name: String) {
      createUser(
        email: $email,
        password: $password,
        name: $name
      ) {
        id
      }
    }
  `

  const variables = {
    email,
    password: password,
    name: name
  }

  return api.request<{ createUser: User }>(mutation, variables)
    .then(r => r.createUser.id)

Answer 1

找到答案了。我在这一行里漏掉了名字。

const { email, password } = event.data

变成这个解决了它

const { email, password, name } = event.data