我是否可以使用XPath将所有数据分离为";“？

Question

我不能用xpath在特定的网站上打印//*@class=“足球主内容”，谢谢！

# -*- coding:UTF-8 -*-

from pyvirtualdisplay import Display
import sys
from bs4 import BeautifulSoup
from selenium import webdriver

display = Display(visible=0, size=(1024, 768))
display.start()

driver = webdriver.Firefox()
driver.get("url")

soup = BeautifulSoup(driver.page_source.encode('utf-8'),'html.parser')
lines = soup.find_elements_by_xpath('//*[@class="footballmaincontent"]/tr')
print lines

driver.close()
display.stop()

Answer 1

尝试下面的代码以获得所需的输出：

lines = ['; '.join([j.text for j in i.find_elements_by_xpath('./td/div | ./td/span/span | ./td/span[not(span)]') if j.text]) for i in driver.find_elements_by_xpath('//*[@class="footballmaincontent"]//tr[position()>2]') if i.text]

for line in lines:
    print line