计算文件中两个字符串之间匹配的行数。

Question

我有个挑战。我有一条短信：

characteristic "type"
   value "A"
   value "B"
   value "C" 
   default-value "B" 
exit 
characteristic "active"
   value "no"
   value "yes"
   default-value "no" 
exit
characteristic "traffic"
   value "disabled" 
   value "enabled"
   default-value "enabled"
exit
characteristic "quota" 
   value "enabled"
   default-value "disabled"
exit
characteristic "redirect"
   value "disabled"
   value "enabled"
   default-value "disabled"
exit

我想知道在“特性”和“退出”之间有多少次是“值”。所以，我希望是这样的：

3
2
2
1
2

我试着使用sed和grep，但我无法得到sed返回'-n -e‘/^特点/、/^exit/ p’的第n位。我相信bash不需要做很多事情就能做到。

谢谢你的帮助。

Answer 1

我想说：

awk '$1 == "characteristic" { ctr = 0 } $1 == "exit" { print ctr } $1 == "value" { ++ctr }' filename

很简单：

$1 == "characteristic" { ctr = 0 }  # Start of a new section: reset counter
$1 == "exit" { print ctr }          # end of section: print counter
$1 == "value" { ++ctr }             # value line: increase counter