我正在编写一个在运行时使用NVRTC编译的CUDA内核(CUDA版本9.2和NVRTC版本7.5),它需要stdint.h头,以便具有int32_t等类型。
如果我编写的内核源代码没有包含,它的工作正常。例如,内核
extern "C" __global__ void f() { ... }编译成PTX代码,其中f被定义为.visible .entry f。
但是如果内核源代码是
#include <stdint.h>
extern "C" __global__ void f() { ... }它报告A function without execution space annotations (__host__/__device__/__global__) is considered a host function, and host functions are not allowed in JIT mode. (也没有extern "C")。
传递-default-device将生成PTX代码.visible .func f,因此不能从主机调用该函数。
是否有一种方法可以在源代码中包含头部,并且仍然有一个__global__条目函数?或者,另一种方法是知道NVRTC编译器在哪个整数大小约定上使用,以便可以手动定义int32_t等类型?
编辑:显示问题的示例程序:
#include <cstdlib>
#include <string>
#include <vector>
#include <memory>
#include <cassert>
#include <iostream>
#include <cuda.h>
#include <cuda_runtime.h>
#include <nvrtc.h>
[[noreturn]] void fail(const std::string& msg, int code) {
std::cerr << "error: " << msg << " (" << code << ')' << std::endl;
std::exit(EXIT_FAILURE);
}
std::unique_ptr<char[]> compile_to_ptx(const char* program_source) {
nvrtcResult rv;
// create nvrtc program
nvrtcProgram prog;
rv = nvrtcCreateProgram(
&prog,
program_source,
"program.cu",
0,
nullptr,
nullptr
);
if(rv != NVRTC_SUCCESS) fail("nvrtcCreateProgram", rv);
// compile nvrtc program
std::vector<const char*> options = {
"--gpu-architecture=compute_30"
};
//options.push_back("-default-device");
rv = nvrtcCompileProgram(prog, options.size(), options.data());
if(rv != NVRTC_SUCCESS) {
std::size_t log_size;
rv = nvrtcGetProgramLogSize(prog, &log_size);
if(rv != NVRTC_SUCCESS) fail("nvrtcGetProgramLogSize", rv);
auto log = std::make_unique<char[]>(log_size);
rv = nvrtcGetProgramLog(prog, log.get());
if(rv != NVRTC_SUCCESS) fail("nvrtcGetProgramLog", rv);
assert(log[log_size - 1] == '\0');
std::cerr << "Compile error; log:\n" << log.get() << std::endl;
fail("nvrtcCompileProgram", rv);
}
// get ptx code
std::size_t ptx_size;
rv = nvrtcGetPTXSize(prog, &ptx_size);
if(rv != NVRTC_SUCCESS) fail("nvrtcGetPTXSize", rv);
auto ptx = std::make_unique<char[]>(ptx_size);
rv = nvrtcGetPTX(prog, ptx.get());
if(rv != NVRTC_SUCCESS) fail("nvrtcGetPTX", rv);
assert(ptx[ptx_size - 1] == '\0');
nvrtcDestroyProgram(&prog);
return ptx;
}
const char program_source[] = R"%%%(
//#include <stdint.h>
extern "C" __global__ void f(int* in, int* out) {
out[threadIdx.x] = in[threadIdx.x];
}
)%%%";
int main() {
CUresult rv;
// initialize CUDA
rv = cuInit(0);
if(rv != CUDA_SUCCESS) fail("cuInit", rv);
// compile program to ptx
auto ptx = compile_to_ptx(program_source);
std::cout << "PTX code:\n" << ptx.get() << std::endl;
}当内核源代码中的//#include <stdint.h>未注释时,它将不再编译。当//options.push_back("-default-device");未注释时,它编译,但不将函数f标记为.entry。
CMakeLists.txt编译它(需要CUDA驱动程序API + NVRTC)
cmake_minimum_required(VERSION 3.4)
project(cudabug CXX)
find_package(CUDA REQUIRED)
set(CMAKE_CXX_STANDARD 14)
set(CMAKE_CXX_STANDARD_REQUIRED 14)
add_executable(cudabug cudabug.cc)
include_directories(SYSTEM ${CUDA_INCLUDE_DIRS})
link_directories(${CUDA_LIBRARY_DIRS})
target_link_libraries(cudabug PUBLIC ${CUDA_LIBRARIES} nvrtc cuda)发布于 2018-08-21 12:42:13
前言:这是一个非常麻烦的答案,并且是针对GNU工具链的(虽然我怀疑问题中的问题也是针对GNU工具链的)。
这里的问题似乎是GNU features.h,它被拖到stdint.h中,然后定义了许多具有默认__host__编译空间的存根函数。这会导致nvrtc爆炸。-default-device选项似乎还会导致解析的glibC编译器特性集,从而使整个nvrtc编译器失败。
您可以通过为标准库预先定义一个功能集来克服这个问题(以一种非常麻烦的方式),它排除了所有的宿主函数。将JIT内核代码更改为
const char program_source[] = R"%%%(
#define __ASSEMBLER__
#define __extension__
#include <stdint.h>
extern "C" __global__ void f(int32_t* in, int32_t* out) {
out[threadIdx.x] = in[threadIdx.x];
}
)%%%";给我买了这个
$ nvcc -std=c++14 -ccbin=g++-7 jit_header.cu -o jitheader -lnvrtc -lcuda
$ ./jitheader
PTX code:
//
// Generated by NVIDIA NVVM Compiler
//
// Compiler Build ID: CL-24330188
// Cuda compilation tools, release 9.2, V9.2.148
// Based on LLVM 3.4svn
//
.version 6.2
.target sm_30
.address_size 64
// .globl f
.visible .entry f(
.param .u64 f_param_0,
.param .u64 f_param_1
)
{
.reg .b32 %r<3>;
.reg .b64 %rd<8>;
ld.param.u64 %rd1, [f_param_0];
ld.param.u64 %rd2, [f_param_1];
cvta.to.global.u64 %rd3, %rd2;
cvta.to.global.u64 %rd4, %rd1;
mov.u32 %r1, %tid.x;
mul.wide.u32 %rd5, %r1, 4;
add.s64 %rd6, %rd4, %rd5;
ld.global.u32 %r2, [%rd6];
add.s64 %rd7, %rd3, %rd5;
st.global.u32 [%rd7], %r2;
ret;
}注意:这在我尝试过的glibC系统上起了作用。它可能无法与其他工具链或libC实现一起工作(如果确实存在这个问题的话)。
发布于 2021-02-04 14:42:57
另一种选择是为一些标准库标头创建备用文件。NVRTC的API支持将头文件内容指定为字符串,并与标题名称相关联--在它为您查看文件系统之前。这种方法是在NVIDIA JITify中采用的,我自己也采用了它来处理其他可能发布或不发布的内容。
要做到这一点,您只需从stdint.h ( limits.h )获取stdint.h的limits.h头存根,我也会附加它,因为它不是很长。或者,您可以自己生成这个存根,以确保您不会错过与标准相关的任何内容。以下是它的工作原理:
stdint.h文件(或cstdint文件(视情况而定)开始;#pragma),并在每个函数声明中添加__device__ __host__或__host__。重要注意事项:要做到这一点需要注意许可证和版权。您将创建一个glibc和/或JITify和/或StackOverflow贡献等的“派生工作”。
现在,我承诺的stdint.h和limits.h来自NVIDIA JITify。我已经对它们进行了调整,使其没有名称空间:
stdint.h
#pragma once
#include <limits.h>
typedef signed char int8_t;
typedef signed short int16_t;
typedef signed int int32_t;
typedef signed long long int64_t;
typedef signed char int_fast8_t;
typedef signed short int_fast16_t;
typedef signed int int_fast32_t;
typedef signed long long int_fast64_t;
typedef signed char int_least8_t;
typedef signed short int_least16_t;
typedef signed int int_least32_t;
typedef signed long long int_least64_t;
typedef signed long long intmax_t;
typedef signed long intptr_t; //optional
typedef unsigned char uint8_t;
typedef unsigned short uint16_t;
typedef unsigned int uint32_t;
typedef unsigned long long uint64_t;
typedef unsigned char uint_fast8_t;
typedef unsigned short uint_fast16_t;
typedef unsigned int uint_fast32_t;
typedef unsigned long long uint_fast64_t;
typedef unsigned char uint_least8_t;
typedef unsigned short uint_least16_t;
typedef unsigned int uint_least32_t;
typedef unsigned long long uint_least64_t;
typedef unsigned long long uintmax_t;
#define INT8_MIN SCHAR_MIN
#define INT16_MIN SHRT_MIN
#if defined _WIN32 || defined _WIN64
#define WCHAR_MIN SHRT_MIN
#define WCHAR_MAX SHRT_MAX
typedef unsigned long long uintptr_t; //optional
#else
#define WCHAR_MIN INT_MIN
#define WCHAR_MAX INT_MAX
typedef unsigned long uintptr_t; //optional
#endif
#define INT32_MIN INT_MIN
#define INT64_MIN LLONG_MIN
#define INT8_MAX SCHAR_MAX
#define INT16_MAX SHRT_MAX
#define INT32_MAX INT_MAX
#define INT64_MAX LLONG_MAX
#define UINT8_MAX UCHAR_MAX
#define UINT16_MAX USHRT_MAX
#define UINT32_MAX UINT_MAX
#define UINT64_MAX ULLONG_MAX
#define INTPTR_MIN LONG_MIN
#define INTMAX_MIN LLONG_MIN
#define INTPTR_MAX LONG_MAX
#define INTMAX_MAX LLONG_MAX
#define UINTPTR_MAX ULONG_MAX
#define UINTMAX_MAX ULLONG_MAX
#define PTRDIFF_MIN INTPTR_MIN
#define PTRDIFF_MAX INTPTR_MAX
#define SIZE_MAX UINT64_MAXlimits.h
#pragma once
#if defined _WIN32 || defined _WIN64
#define __WORDSIZE 32
#else
#if defined __x86_64__ && !defined __ILP32__
#define __WORDSIZE 64
#else
#define __WORDSIZE 32
#endif
#endif
#define MB_LEN_MAX 16
#define CHAR_BIT 8
#define SCHAR_MIN (-128)
#define SCHAR_MAX 127
#define UCHAR_MAX 255
enum {
_JITIFY_CHAR_IS_UNSIGNED = (char)-1 >= 0,
CHAR_MIN = _JITIFY_CHAR_IS_UNSIGNED ? 0 : SCHAR_MIN,
CHAR_MAX = _JITIFY_CHAR_IS_UNSIGNED ? UCHAR_MAX : SCHAR_MAX,
};
#define SHRT_MIN (-32768)
#define SHRT_MAX 32767
#define USHRT_MAX 65535
#define INT_MIN (-INT_MAX - 1)
#define INT_MAX 2147483647
#define UINT_MAX 4294967295U
#if __WORDSIZE == 64
# define LONG_MAX 9223372036854775807L
#else
# define LONG_MAX 2147483647L
#endif
#define LONG_MIN (-LONG_MAX - 1L)
#if __WORDSIZE == 64
#define ULONG_MAX 18446744073709551615UL
#else
#define ULONG_MAX 4294967295UL
#endif
#define LLONG_MAX 9223372036854775807LL
#define LLONG_MIN (-LLONG_MAX - 1LL)
#define ULLONG_MAX 18446744073709551615ULLhttps://stackoverflow.com/questions/50565200
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