计算器碰撞

Question

当我按“计算”键时，我试图创建一个计算考试笔记的应用程序，没有任何小数，它显示答案，但是如果有小数，它就会崩溃。

public class MainActivity extends AppCompatActivity {

    TextView Result;
    EditText Number1 , Number2, Number3, Number4, Number5, Number6;
    Button Calculate;

    float result_num;
    int num1,num2,num3,num4,num5,num6;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Result = (TextView)findViewById(R.id.Result);

        Number1 = (EditText)findViewById(R.id.Number1);
        Number2 = (EditText)findViewById(R.id.Number2);
        Number3 = (EditText)findViewById(R.id.Number3);
        Number4 = (EditText)findViewById(R.id.Number4);
        Number5 = (EditText)findViewById(R.id.Number5);
        Number6 = (EditText)findViewById(R.id.Number6);

        Calculate = (Button)findViewById(R.id.Calculate);

        Calculate.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                num1 = Integer.parseInt(Number1.getText().toString());
                num2 = Integer.parseInt(Number2.getText().toString());
                num3 = Integer.parseInt(Number3.getText().toString());
                num4 = Integer.parseInt(Number4.getText().toString());
                num5 = Integer.parseInt(Number5.getText().toString());
                num6 = Integer.parseInt(Number6.getText().toString());

                result_num = ((((num1 + num2 + num3 + num4) / 4) * 20) / 100) + ((((num5 + num6) / 2) * 80) / 100);
                Result.setText(String.valueOf(result_num));

            }
        });
    }
}

Answer 1

使用浮动而不是整数。整数无法用小数点解析(并对)数字进行操作。

添加:这是错误检查代码：

try {
  num1 = Double.parseDouble(Number1.getText().toString());
  num2 = Double.parseDouble(Number2.getText().toString());
  ...
}
catch (NumberFormatException ex) {
  Toast.makeText(this, "Error: " + ex.getMessage(), Toast.LENGTH_LONG).show();
}

Answer 2

基本上，您试图在下面的代码中将Double或Float值解析为Integer类型：

Integer.parseInt(Number1.getText().toString());

您的代码不适用于十进制值。但您可以将其更改为双值，如下所示：

double value1 = Double.parseDouble(Number1.getText().toString());