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社区首页 >问答首页 >INNER with条件- Mysql

INNER with条件- Mysql
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Stack Overflow用户
提问于 2019-01-12 10:50:12
回答 2查看 79关注 0票数 1

如果条件为真,我正在尝试进行内连接,但它不起作用,我已经尝试了以下两种方法:

代码语言:javascript
复制
IF chat.tipo = 'vitima' THEN
   INNER JOIN vitima ON vitima.id_vit = chat.id_tipo

ELSE
   INNER JOIN terceiro ON terceiro.id_ter = chat.id_tipo

代码语言:javascript
复制
IF(chat.tipo = 'vitima', 
        INNER JOIN vitima ON vitima.id_vit = chat.id_tipo,
        INNER JOIN terceiro ON terceiro.id_ter = chat.id_tipo)

但两者都会产生错误,我想要的是,如果类型等于"vitima“,它会在一个表中执行内部noin,否则在另一个表中。

完整查询:

代码语言:javascript
复制
SELECT ocorrencia.id_oco, 
        (SELECT GROUP_CONCAT(c.id_oco ORDER BY c.id_oco DESC) FROM ocorrencia as c WHERE c.id_sup_oco = ocorrencia.id_sup_oco) as grouped_ids, 
        ocorrencia.id_sup_oco, 
        chat.id_tipo,
        suporte_oco.data_sup,
        suporte_oco.placa_sup,
        suporte_oco.sinistro_sup,
        suporte_oco.prefixo_sup,
        ocorrencia.id_emp_oco,
        IF(chat.tipo = 'vitima', vitima.nome_vit, terceiro.nome_ter) as nome,
        chat.tipo

        FROM chat 
        INNER JOIN ocorrencia ON ocorrencia.id_oco = chat.id_oco_cha 
        INNER JOIN suporte_oco ON suporte_oco.id_sup = ocorrencia.id_sup_oco

        IF chat.tipo = 'vitima'
            INNER JOIN vitima ON vitima.id_vit = chat.id_tipo
        ELSE
            INNER JOIN terceiro ON terceiro.id_ter = chat.id_tipo

        WHERE chat.id_user = '20' OR chat.id_user_req = '20' GROUP BY (chat.id_oco_cha) ORDER BY chat.data DESC
EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2019-01-12 10:58:01

这并不准确,但我认为这将非常接近您正在尝试做的事情:

代码语言:javascript
复制
LEFT JOIN vitima ON vitima.id_vit = chat.id_tipo AND chat.tipo = 'vitima'
LEFT JOIN terceiro ON terceiro.id_ter = chat.id_tipo AND chat.tipo != 'vitima'
...
WHERE (chat.tipo = 'vitima' AND vitima.id_vit IS NOT NULL)
    OR (chat.tipo != 'vitima' AND terceiro.id_ter IS NOT NULL)

LEFT JOIN条件强制执行您的规则,而WHERE条件模拟和INNER JOIN,因为它要求存在这些记录。

使用您发布的完整查询,它将如下所示:

代码语言:javascript
复制
SELECT ocorrencia.id_oco, 
    (SELECT GROUP_CONCAT(c.id_oco ORDER BY c.id_oco DESC) FROM ocorrencia as c WHERE c.id_sup_oco = ocorrencia.id_sup_oco) as grouped_ids, 
    ocorrencia.id_sup_oco, 
    chat.id_tipo,
    suporte_oco.data_sup,
    suporte_oco.placa_sup,
    suporte_oco.sinistro_sup,
    suporte_oco.prefixo_sup,
    ocorrencia.id_emp_oco,
    IF(chat.tipo = 'vitima', vitima.nome_vit, terceiro.nome_ter) as nome,
    chat.tipo

FROM chat 
    INNER JOIN ocorrencia ON ocorrencia.id_oco = chat.id_oco_cha 
    INNER JOIN suporte_oco ON suporte_oco.id_sup = ocorrencia.id_sup_oco
    LEFT JOIN vitima ON vitima.id_vit = chat.id_tipo AND chat.tipo = 'vitima'
    LEFT JOIN terceiro ON terceiro.id_ter = chat.id_tipo AND chat.tipo != 'vitima'

WHERE chat.id_user = '20' OR chat.id_user_req = '20'
    AND (
        (chat.tipo = 'vitima' AND vitima.id_vit IS NOT NULL)
        OR (chat.tipo != 'vitima' AND terceiro.id_ter IS NOT NULL)
    )
GROUP BY (chat.id_oco_cha) ORDER BY chat.data DESC
票数 1
EN

Stack Overflow用户

发布于 2019-01-12 10:54:10

您不能在join中使用条件,可能更容易使用union,如下所示:

代码语言:javascript
复制
select * from chat inner join vitima ON 
union all
select * from chat inner join terceiro ON chat.tipo <> 'vitima' AND terceiro.id_ter = chat.id_tipo

我能想到的另一个变体是:

代码语言:javascript
复制
select *
from chat, vitima, terceiro
where
(chat.tipo = 'vitima' AND vitima.id_vit = chat.id_tipo)
OR
(chat.tipo <> 'vitima' AND terceiro.id_ter = chat.id_tipo)
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/54156385

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