用getID3在浏览器中显示图像

Question

我希望创建一个php文件，当调用为html的img标记中的src参数时，该文件将返回mp3歌曲的图像。就像这样：

<img src="/imageReturn.php?song=SongName">

为了从mp3文件中获取图像，我使用了getID3库。我的PHP代码：

$song= $_GET["song"];
require_once("getID3-1.9.15/getid3/getid3.php");
$Path=$song.".mp3";

$getID3 = new getID3;
$OldThisFileInfo = $getID3->analyze($Path);
if(isset($OldThisFileInfo['comments']['picture'][0]))
{
    $ImageBase='data:'.$OldThisFileInfo['comments']['picture'][0]['image_mime'].';charset=utf-8;base64,'.base64_encode($OldThisFileInfo['comments']['picture'][0]['data']);
}

header('Content-Type: image/jpeg');
echo $ImageBase;

问题是我无法获得php显示的图像。怎么修呢？

Answer 1

您不必将图像编码为base64，您可以直接对图像数据进行echo。

$getID3 = new getID3;
$OldThisFileInfo = $getID3->analyze($Path);
if(isset($OldThisFileInfo['comments']['picture'][0]))
{
    header('Content-Type: ' . $OldThisFileInfo['comments']['picture'][0]['image_mime']);
    echo $OldThisFileInfo['comments']['picture'][0]['data'];
    die;
}