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使用子选择值进行PostgreSQL计算
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Stack Overflow用户
提问于 2018-04-26 13:22:50
回答 1查看 599关注 0票数 0

使用PostgreSQL 9.3,我试图根据电子邮件表中的子选择结果计算一些值。下面是我想要做的事情,这当然会导致SQL错误,因为您不能在SELECT中引用别名值:

代码语言:javascript
复制
SELECT 
    email.key,
    email.col1,
    email.col2,
    (SELECT count(sent.subscriber_key) FROM sent WHERE sent.email_id = email.key) AS sent_count,
    (SELECT count(bounce.subscriber_key) FROM bounce WHERE bounce.email_id = email.key) AS bounce_count,
    ((bounce_count / sent_count) * 100) as bounce_pct
FROM
    email
ORDER BY 
    email.key

我尝试将子选择逻辑移到WITH子句中:

代码语言:javascript
复制
WITH
    sent_tmp AS (SELECT count(sent.subscriber_key) as count FROM sent INNER JOIN email ON sent.send_id = email.key),
    bounce_tmp AS (SELECT count(bounce.subscriber_key) as count FROM bounce INNER JOIN email ON bounce.send_id = email.key)
SELECT 
    email.key,
    email.col1,
    email.col2,
    email.sent_date,
    sent_tmp.count,
    bounce_tmp.count,
    ((bounce_tmp.count / sent_tmp.count) * 100) as bounce_pct
FROM
    email,
    sent_tmp,
    bounce_tmp
ORDER BY 
    email.key

...and我尝试将它移到FROM子句中:

代码语言:javascript
复制
SELECT 
    email.key,
    email.col1,
    email.col2,
    sent_count,
    bounce_count,
    ((bounce_count / sent_count) * 100) as bounce_pct
FROM
    email,
    (SELECT count(sent.subscriber_key) FROM sent INNER JOIN email ON sent.send_id = email.key) AS sent_count,
    (SELECT count(bounce.subscriber_key) FROM bounce INNER JOIN email ON bounce.send_id = email.key) AS bounce_count
ORDER BY 
    email.key

.,但无论哪种方式,都会产生无效的发送和弹回数字。(每封邮件的号码都是一样的。)我可能不了解PostgreSQL查询语法的执行顺序,或者没有对电子邮件表中的每一行结果计算子选择。

如果有人能指点我在正确的方向,并让我知道什么是可能的,它将不胜感激!在将子选择逻辑移到WITH或FROM中时,是否缺少一些关键语法?我需要使用命名变量吗?功能?

我意识到可以添加另一个子subselect,它将在发送表和反射表中重新计算subscriber_key列,但为了效率起见,我试图避免重新计数。(以及可读性,就这一点而言)

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回答 1

Stack Overflow用户

回答已采纳

发布于 2018-04-26 14:33:45

简单的解决方案是计算外部查询中的值:

代码语言:javascript
复制
SELECT key, col1, col2, sent_count, bounce_count,
       100.0 * bounce_count / sent_count AS bounce_pct
FROM (SELECT key, col1, col2,
            (SELECT count(sent.subscriber_key)
             FROM sent
             WHERE sent.email_id = email.key
            ) AS sent_count,
            (SELECT count(bounce.subscriber_key)
             FROM bounce
             WHERE bounce.email_id = email.key
            ) AS bounce_count
      FROM email
     ) q
ORDER BY key;
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/50044136

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