路径(‘accounts/’，include(accounts.urls))，NameError: name 'accounts‘未定义

Question

我只是做了一个克隆的ProductHunt.com网站，当我寻址的网址，我得到错误的名称错误！当我输入'localhost:8000/accounts/signup‘时，它应该会带我到html页面，这是我测试时所做的！主urls.py如下所示：

from django.contrib import admin
from django.urls import path, include
from products import views

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', views.home, name="home"),
    path('accounts/', include(accounts.urls)),
]

因此，它将转到accounts文件夹urls.py，如:从django.urls导入路径，包含从.import视图

urlpatterns = [
    path('signup', views.signup, name="signup"),
    path('login', views.login, name="login"),
    path('logout', views.logout, name="logout"),
]

然后，这将转到views.py，它看起来像:从django.shortcuts导入呈现

def signup(request):
    return render(request, 'accounts/signup.html')

def login(request):
    return render(request, 'accounts/login.html')

def logout(request):
    return render(request, 'accounts/signup.html')

最后，我的html是：

{% extends 'base.html %}

{% block content %}

signup!

{% endblock %}

为什么我得到了一个名字错误：

  File "C:\Users\Kiran\Desktop\producthunt-project\producthunt\urls.py", line 8,
 in <module>
    path('accounts/', include(accounts.urls)),
NameError: name 'accounts' is not defined

帮帮我，谢谢，

Answer 1

替换您的代码

urlpatterns = [
    ...
    path('accounts/', include(accounts.urls)),
]

使用

urlpatterns = [
    ...
    path('accounts/', include('accounts.urls')),
]

并确保您在安装的应用程序中添加了“帐户”。