python:使用regex查找特定单词

Question

这是我的字符串：

在你的xxxx银行的“借方/信贷/存款/.”上，你的交易密码为“1897.00”的“xxxx”以“0000”结尾的卡片是“0000”

xxxx - string，0000 -数字

我想取单引号(‘)中的所有值。

，这就是我尝试过的：

[a-z ]+, ([a-z]+)[a-z ]+([0-9\.]+)到这里是正确的

现在我想取(借方/信用/.)，我在做：

在你的[a-z]+银行[a-z]+[a-z ]+([0-9]+)[a-z ]+[0-9]上

更好的方法应该是什么？

Answer 1

做到这一点的最安全和最具表现力的方法是在两个单引号之间匹配不是单引号的任何内容(在这种情况下，贪婪或懒惰并不重要)：

'[^']*'

演示

代码示例：

import re    
regex = r"'[^']*'"    
test_str = '''one time password for your transaction at, 'xxxx' of inr '1897.00' \
on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000'''
matches = re.finditer(regex, test_str)
for match in matches:
    print ("Match was found at {start}-{end}: {match}".format(start = match.start(), end = match.end(), match = match.group()))

Answer 2

您要寻找的正则表达式是简单的r"'(.*?)'"。下面是一个示例程序：

import re

regex = r"'(.*?)'"

test_str = "\"one time password for your transaction at, 'xxxx' of inr '1897.00' on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000\""

matches = re.finditer(regex, test_str)

for matchNum, match in enumerate(matches):
    print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

其中产出：

Match 0 was found at 44-50: 'xxxx'
Match 1 was found at 58-67: '1897.00'
Match 2 was found at 86-113: 'debit/credit/deposit/....'
Match 3 was found at 126-132: '0000'

在这里了解有关使用regex的更多信息：https://regex101.com/

Answer 3

如果你想要单引号中的所有字符，

import re
string = "'xxxx' of inr '1897.00' on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000"
all_matches = re.findall(r"\'.+?\'",string)
print all_matches