PyRal getAttachment

Question

我有一个相当简单的用例，但是我不理解我收到的错误信息。

我正在使用requests和pyral模块，pyral (http://pyral.readthedocs.io/en/latest/interface.html#)实际上只是Rally的Restful的包装器。我的目标是从Rally ( CA产品) UserStory获取一个文件(附件)，并将其存储到本地文件系统中。

对于上下文，这里是我的环境设置(通过Rally身份验证并创建一个对象)。我显然删除了身份验证信息。

from pyral import Rally, rallyWorkset

options = [arg for arg in sys.argv[1:] if arg.startswith('--')]
args = [arg for arg in sys.argv[1:] if arg not in options]
server, user, password, apikey, workspace, project = rallyWorkset(options)
rally = Rally(server='rally1.rallydev.com', 
user='**********', password='***********', 
          apikey="**************",
          workspace='**************', project='**************',
          server_ping=False)

在此之后，我只获得一个用户故事的响应对象(请参阅US845的查询)，我这样做只是为了简化问题。

r = rally.get('UserStory', fetch = True, projectScopeDown=True, query = 'FormattedID = US845')

然后，我使用内置迭代器从RallyRESTResponse对象获取用户故事。

us = r.next()

从这里看，我应该能够轻松地使用接受工件(us)和文件名(附件名称)的getAttachment()方法。我可以使用getAttachmentNames(us)返回附件名称的列表。当我尝试这样的事情时，问题就出现了。

attachment_names = rally.getAttachmentNames(us) #get attachments for this UserStory
attachment_file = rally.getAttachment(us, attachment_names[0]) #Try to get the first attachment 

返回如下错误

Traceback (most recent call last):

File "<ipython-input-81-a4a342a59c5a>", line 1, in <module>
attachment_file = rally.getAttachment(us, attachment_names[0])

File "C:\Miniconda3\lib\site-packages\pyral\restapi.py", line 1700, in getAttachment
att.Content = base64.decodebytes(att_content.Content)  # maybe further txfm to Unicode ?

File "C:\Miniconda3\lib\base64.py", line 552, in decodebytes
_input_type_check(s)

File "C:\Miniconda3\lib\base64.py", line 520, in _input_type_check
raise TypeError(msg) from err

TypeError: expected bytes-like object, not str

如果我尝试使用

test_obj = rally.getAttachments(us)

返回如下错误：

Traceback (most recent call last):

File "<ipython-input-82-06a8cd525177>", line 1, in <module>
rally.getAttachments(us)

File "C:\Miniconda3\lib\site-packages\pyral\restapi.py", line 1721, in getAttachments
attachments = [self.getAttachment(artifact, attachment_name) for attachment_name in attachment_names]

File "C:\Miniconda3\lib\site-packages\pyral\restapi.py", line 1721, in <listcomp>
attachments = [self.getAttachment(artifact, attachment_name) for attachment_name in attachment_names]

File "C:\Miniconda3\lib\site-packages\pyral\restapi.py", line 1700, in getAttachment
att.Content = base64.decodebytes(att_content.Content)  # maybe further txfm to Unicode ?

File "C:\Miniconda3\lib\base64.py", line 552, in decodebytes
_input_type_check(s)

File "C:\Miniconda3\lib\base64.py", line 520, in _input_type_check
raise TypeError(msg) from err

TypeError: expected bytes-like object, not str

似乎我从根本上误解了这个方法所需的参数？以前有人能成功地做到这一点吗？值得注意的是，我在使用与上面类似的工作流的addAttachment()方法时没有问题。我尝试过用字节()方法将文件名(string)转换为utf-8，但这没有帮助。

我还在pyral源代码中查看了这个示例，但是在尝试执行这个示例时，我收到了完全相同的错误。

attachments.py

Answer 1

它看起来像restapi.py脚本中的问题--在base64库中没有任何解码方法：

att.Content = base64.decodebytes(att_content.Content)

所有可用的方法都在：RFC 3548: Base16，Base32，Base64数据编码中描述，因此，解决方法是用base64.b64decode代替restapi.py中的解码器。至少它对我有用。

例如，Mac的位置：

/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pyral/restapi.py

Answer 2

我使用了下面的代码来获取所有附件，因为getAttachments不像预期的那样工作。它将使用相同的名称在当前dir中创建一个文件。

import sys
import string
import base64
from pyral import rallyWorkset, Rally,RallyRESTResponse

rally = Rally(server, user=USER_NAME, password=PASSWORD, workspace=workspace, project=project)
criterion = 'FormattedID = US57844'
response = rally.get('HierarchicalRequirement',  query=criterion, order="FormattedID",pagesize=200, limit=400, projectScopeDown=True)

artifact = response.next()
context, augments = rally.contextHelper.identifyContext()
for att in artifact.Attachments:
    resp = rally._getResourceByOID(context, 'AttachmentContent', att.Content.oid, project=None)
    if resp.status_code not in [200, 201, 202]:
        break
    res = RallyRESTResponse(rally.session, context, "AttachmentContent.x", resp, "full", 1)
    if res.errors or res.resultCount != 1:
        print("breaking the for loop")
    att_content = res.next()
    cont = att_content.Content
    x = base64.b64decode(cont)
    output = open(att.Name, 'wb') 
    output.write(x)