从自定义共享模块角度5绘制子组件

Question

我对棱角很陌生，很难在另一个组件中显示一个组件。

模式:我有一个导航栏，使路由器出口使用路由导航到"component1“。然后，在组件1中，我将标记保持不变。如果我导航到组件-2使用路由，它正确地呈现。

main.component.html

<div class="flex">
    <div>
            <router-outlet name="navbar"></router-outlet>
            <div class="container-fluid col-10 offset-2">
                <div class="row">
                    <div class="col-12">
                        <div class="card jh-card shadow">
                            <router-outlet></router-outlet>
                            <router-outlet name="popup"></router-outlet>
                        </div>
                        <jhi-footer></jhi-footer>
                    </div>
                </div>
            </div>
    </div>
</div>

component1.module.ts

import { NgModule, CUSTOM_ELEMENTS_SCHEMA } from '@angular/core';
import { RouterModule } from '@angular/router';

import { ClientSharedModule } from '../shared';
import { COMPONENT1_ROUTE, Component1 } from './';

@NgModule({
    imports: [
      ClientSharedModule,
      RouterModule.forRoot([ COMPONENT1_ROUTE ], { useHash: true }),
    ],
    declarations: [
      Component1
    ],
    entryComponents: [
    ],
    providers: [
    ],
    schemas: [CUSTOM_ELEMENTS_SCHEMA]
})
export class Component1Module {}

component1.component.html

<div class="row">
    <div class="col-md-1"></div>
    <div class="col-md-10">
        <div class=""> searchBar</div>
        <div> some text</div>
    </div>
    <div class="col-md-1"></div>
</div>
<component-2>test</component-2>

component-2.component.ts

import { Component, OnInit } from '@angular/core';

@Component({
  selector: 'component-2',
  templateUrl: './component-2.component.html',
  styles: [
      'component-2.scss'
  ]
})
export class Component2 implements OnInit {

  constructor() {
      console.log('COMPONENT CONSTRUCTED');
  }

  ngOnInit() {
      console.log('COMPONENT INITIALISED');
  }

}

custom-shared.module.ts

import {CUSTOM_ELEMENTS_SCHEMA, NgModule} from '@angular/core';
import {

    Component2Module
} from './component-2/component-2.module';

@NgModule({
  imports: [
    Component2Module,
  ],
  declarations: [
  ],
  entryComponents: [],
  exports: [
    Component2Module
  ],

  schemas: [CUSTOM_ELEMENTS_SCHEMA]
})
export class CustomSharedModule { }

component-2.module.ts

import {NgModule, CUSTOM_ELEMENTS_SCHEMA} from '@angular/core';
import {RouterModule} from '@angular/router';
import {ClientSharedModule} from '../../shared';
import {
    Component2Details,
    Component2,
    component2Route
} from './';

const ENTITY_STATE = [
    component2Route,
];

@NgModule({
  imports: [
      ClientSharedModule,
      RouterModule.forChild(ENTITY_STATE)
  ],
  declarations: [
      Component2,
      Component2Details
  ],
  entryComponents: [
      Component2,
      Component2Details
  ],
  schemas: [CUSTOM_ELEMENTS_SCHEMA]
})

export class Component2Module {
    constructor() {}
}

我换了零件的真名。实际上，我在编译时和执行时都没有错误。我相信这与范围或注射有关，但我找不到解决办法。如果有人能给我一些帮助，我会非常感激的。

附加信息: Jhipster v4.14.2单片应用程序。角5+

提前谢谢。文森特湾

Answer 1

问题解决了，我的错误是，如果我在compent2模块中导出component2，然后在我的共享模块中导入这个模块，那么在我导入共享模块的任何地方，组件都是可用的。

解决方案是直接从共享模块导出/声明component2。然后，无论我在哪里导入共享模块，它都是可用的。

希望这能帮到一些人。再见