如何获取50多个Jira问题？

Question

我正在尝试使用API从Jirà获取所有任务。我找到了工作代码

public class CustomJiraRestClient {

    private static final String JIRA_URL = "http://jira-dev:8080";
    private static final String JIRA_ADMIN_USERNAME = "admin";
    private static final String JIRA_ADMIN_PASSWORD = "admin";

    public static void main(String[] args) throws Exception {
        // Construct the JRJC client
        System.out.println(String.format("Logging in to %s with username '%s' and password '%s'", JIRA_URL, JIRA_ADMIN_USERNAME, JIRA_ADMIN_PASSWORD));
        JiraRestClientFactory factory = new AsynchronousJiraRestClientFactory();
        URI uri = new URI(JIRA_URL);
        JiraRestClient client = factory.createWithBasicHttpAuthentication(uri, JIRA_ADMIN_USERNAME, JIRA_ADMIN_PASSWORD);

        // Invoke the JRJC Client
        Promise<User> promise = client.getUserClient().getUser("admin");
        User user = promise.claim();

        Promise<SearchResult> searchJqlPromise = client.getSearchClient().searchJql("project = MYPURRJECT AND status in (Closed, Completed, Resolved) ORDER BY assignee, resolutiondate");

        for (Issue issue : searchJqlPromise.claim().getIssues()) {
            System.out.println(issue.getSummary());
        }

        // Done
        System.out.println("Example complete. Now exiting.");
        System.exit(0);
    }
}

但是有一个问题：-只显示前50个条目。在通常情况下，图形界面-一个有50个条目的页面。请帮帮我，我怎么能一次得到所有的记录？或者如何指定所需的页或项。

我找到了方法：

• searchResult.getMaxResults(); -所有记录的数目(n)
• 每页searchResult.getTotal();条目数(50)
• searchResult.getStartIndex(); -第一个元素的数目(0)

但我不能把它们放在任何地方使用。我能认出他们，但这没有任何意义。

下面是我使用的软件版本：

• Jira版本: 7.2.13
• 亚特兰-形象-消费者(com.atlassian.image:atlassian-image-consumer:1.0.1:jar)
• 卡罗尔(卡罗尔:卡罗尔:1.5.2:jar)
• 卡罗尔-属性(卡罗尔:卡罗尔-属性:1.5.2:jar)
• 数据文件( datafile :datafile:1.3.3:jar)
• hibernate (hibernate:hibernate:2.1.8亚特兰:jar)
• image4j (org.jClon:Image4j:0.7:jar)
• JCaptcha (com.octo.captcha:jcaptcha-api:2.0-alpha-1:jar)
• JCaptcha (com.octo.captcha:jcaptcha:2.0-alpha-1:jar)
• (jfree:jcommon:1.0.8:jar)
• jfreechart (jfree:jfreechart:1.0.13:jar)
• JSCalendar (1.0)
• jStyleParser (net.sf.cssbox:jstyleparser:1.16-atlassian-1:jar)
• 用于XML的流API (javax.xml.stream:stax:1.0-2:jar)
• TinyMCE-TinyMCE (4.4.0)
• xapool (xapool:xapool:1.3.1:jar)

Answer 1

简单地看一下API文档，我会说您需要使用重载的searchJql(String jql, int maxResults, int startAt)并指定maxResults参数。

Answer 2

我使用这个简单的循环进行分页。

    List<Issue> issues = new ArrayList<>();
    SearchRestClient searchClient = restClient.getSearchClient();
    Set<String> set = new HashSet<String>();
    set.add("*all");  /* you can use simply null set if you dont need all values  */
    int start = 0;
    int maxPerPage = 25;  /* batch size (max 50) */
    int total = 0;
    do {
        SearchResult result = searchClient.searchJql(JQL, maxPerPage, start, set)
                .claim();
        total = result.getTotal();
        start += maxPerPage;
        result.getIssues().iterator().forEachRemaining(issues::add);
    } while (total > start );

现在所有问题都出现在issues列表中。

Answer 3

我建议使用以下功能。

public List<Issue> getIssuesList(String query) {

    boolean flag = false;
    int start = 0, end=Constants.MAX_RESULTS_PER_PAGE, totalResults = 0;
    List<Issue> issueList = new ArrayList<Issue>();
    SearchResult searchResult;
    do {
        Promise<SearchResult> searchJqlPromise = client.getSearchClient().searchJql(query,end,start, null);

        searchResult = searchJqlPromise.claim();
        if(flag==false) {
            totalResults = searchResult.getTotal();
            flag=true;
        };
        List<Issue> res = (List<Issue>) searchResult.getIssues();
        issueList.addAll(res);
        
        start = start + Constants.MAX_RESULTS_PER_PAGE;
        totalResults -= Constants.MAX_RESULTS_PER_PAGE;
        
    } while(totalResults>0);
    
    return issueList;

}