处理--使物体消失并在一定的时间范围内出现。

Question

这是我目前的代码：

int doorCounter = 0;

void setup()
{
 size(512, 348); //width and height of screen
 doorCounter = (int)random(180,300);
}

void draw()
{
 display();
 doorCounter = doorCounter - 1; // Decrease count by 1
 if (doorCounter <= 0) 
  {
   fill(255);
   rect(420, 190, 55, 100); //house door outline
   rect(435, 210, 25, 25, 7); // house door window
   ellipse(435, 255, 8, 8); // house door handle 
   doorCounter = (int)random(180,480); 
  }
}

void display()
{
  fill(255);
  rect(420, 190, 55, 100); //house door outline
  fill(0,0,0); // fill the following polygons in black
  rect(435, 210, 25, 25, 7); // house door window
  ellipse(435, 255, 8, 8); // house door handle
}

然而，这段代码所做的只是使对象消失了一秒，并使它立即重新出现。如何使物体在随机间隔内消失3-8秒，就像物体在屏幕上仍然存在的情况下，每3-8秒消失一次？

我不知道我想要达到的目标是否有意义，所以请随意提问。

Answer 1

一种方法是使用时间戳并检查从时间戳中经过的时间，如下所示：

int min_time = 3000; // in ms
int max_time = 8000; // in ms

int time_frame = (int)random(min_time, max_time);

int time_stamp = 0;

boolean show_door = true;

void setup()
{
  size(512, 348); //width and height of screen
}

void draw()
{
  background(200);

  int time_passed = millis() - time_stamp;

  if (time_passed < time_frame && show_door) {
    display();
  } else if (time_passed >= time_frame) {
    time_stamp = millis();
    time_frame = (int)random(min_time, max_time);
    show_door = !show_door;
  }
}

void display()
{
  fill(255);
  rect(420, 190, 55, 100); //house door outline
  fill(0, 0, 0); // fill the following polygons in black
  rect(435, 210, 25, 25, 7); // house door window
  ellipse(435, 255, 8, 8); // house door handle
}