当我想在Python中使用C++多态性时,我对C++有一种奇怪的行为。下面是我的问题的一个简单例子:
import polymorphism as plm
a = plm.mylist()
print(a)
a[0].print()
a[1].print()此脚本的输出是
MyBase,MyDerived MyBase MyBase
但预期的产出是
MyBase,MyDerived MyBase MyDerived
因为mylist返回一个std::vector,它包含派生类(MyDerived)的一个实例作为第二个成员。奇怪的是,当我作为一个整体打印列表时,MyDerived就被识别了。
下面是C++代码的头文件:
/* polymorphism.hpp */
#ifndef POLYMORPHISM_HPP
#define POLYMORPHISM_HPP
#include <vector>
class MyBase
{
public:
virtual void print() const;
};
class MyDerived : public MyBase
{
public:
virtual void print() const;
};
std::vector<MyBase*> mylist();
#endif以下是cpp文件:
#include "polymorphism.hpp"
#include <iostream>
#include <pybind11/stl.h>
#include <pybind11/pybind11.h>
void MyBase::print() const
{ std::cout << "MyBase" << std::endl; }
void MyDerived::print() const
{ std::cout << "MyDerived" << std::endl; }
std::vector<MyBase*> mylist()
{
std::vector<MyBase*> list(2);
list[0] = new MyBase();
list[1] = new MyDerived();
return list;
}
PYBIND11_MODULE(polymorphism, m)
{
pybind11::class_<MyBase>(m, "MyBase")
.def(pybind11::init<>())
.def("print", &MyBase::print)
.def("__repr__", [](const MyBase &a) { return "MyBase"; });
pybind11::class_<MyDerived, MyBase>(m, "MyDerived")
.def(pybind11::init<>())
.def("print", &MyDerived::print)
.def("__repr__", [](const MyDerived &a) { return "MyDerived"; });
m.def("mylist", &mylist, "return a list");
}编辑:更令人惊讶的是,当我删除MyDerived的"print“绑定时,我会得到以下错误消息
MyBase,MyDerived MyBase 回溯(最近一次调用): 文件"test.py",第8行 A1.() AttributeError:'polymorphism.MyDerived‘对象没有属性'print’
这个消息似乎意味着MyDerived被很好地识别,而错误的打印版本被调用(如果我理解的话)。
编辑2:这是一个使用蹦床类的版本。但是,这个版本会导致同样的错误输出。
/* polymorphism.hpp */
#ifndef POLYMORPHISM_HPP
#define POLYMORPHISM_HPP
#include <vector>
#include <pybind11/stl.h>
#include <pybind11/pybind11.h>
class MyBase
{
public:
virtual void print() const;
};
class MyDerived : public MyBase
{
public:
virtual void print() const;
};
std::vector<MyBase*> mylist();
class PyMyBase : public MyBase
{
public:
using MyBase::MyBase; // Inherit constructors
void print() const override { PYBIND11_OVERLOAD(void, MyBase, print ); }
};
class PyMyDerived : public MyDerived
{
public:
using MyDerived::MyDerived; // Inherit constructors
void print() const override { PYBIND11_OVERLOAD(void, MyDerived, print);}
};
#endif下面是对应的cpp文件:
/* polymorphism.cpp */
#include "polymorphism.hpp"
#include <iostream>
void MyBase::print() const
{ std::cout << "MyBase" << std::endl; }
void MyDerived::print() const
{ std::cout << "MyDerived" << std::endl; }
std::vector<MyBase*> mylist()
{
std::vector<MyBase*> list(2);
list[0] = new MyBase();
list[1] = new MyDerived();
return list;
}
PYBIND11_MODULE(polymorphism, m)
{
pybind11::class_<MyBase, PyMyBase>(m, "MyBase")
.def(pybind11::init<>())
.def("print", &MyBase::print)
.def("__repr__", [](const MyBase &a) { return "MyBase"; });
pybind11::class_<MyDerived, PyMyDerived>(m, "MyDerived")
.def(pybind11::init<>())
.def("print", &MyDerived::print)
.def("__repr__", [](const MyDerived &a) { return "MyDerived"; });
m.def("mylist", &mylist, "return a list");
}发布于 2018-04-04 06:49:54
我不知道为什么,但是pybind11似乎对mylist()中的原始指针有问题。如果将返回类型更改为vector<unique_ptr<MyBase>>,则示例将正确工作。下面的示例编译为python模块example并生成预期的输出。
example.cpp:
#include <pybind11/stl.h>
#include <pybind11/pybind11.h>
#include <iostream>
#include <memory>
#include <vector>
class MyBase {
public:
virtual void print() const {
std::cout << "MyBase::print()" << std::endl;
}
};
class MyDerived : public MyBase {
public:
virtual void print() const override {
std::cout << "MyDerived::print()" << std::endl;
}
};
std::vector<std::unique_ptr<MyBase>> mylist() {
std::vector<std::unique_ptr<MyBase>> v;
v.push_back(std::make_unique<MyBase>());
v.push_back(std::make_unique<MyDerived>());
return v;
}
PYBIND11_MODULE(example, m) {
pybind11::class_<MyBase>(m, "MyBase")
.def(pybind11::init<>())
.def("print", &MyBase::print)
.def("__repr__", [](MyBase const&) { return "MyBase"; });
pybind11::class_<MyDerived>(m, "MyDerived")
.def(pybind11::init<>())
.def("print", &MyDerived::print)
.def("__repr__", [](MyDerived const&) { return "MyDerived"; });
m.def("mylist", &mylist, "returns a list");
}python外壳:
>>> import example
>>> l = example.mylist()
>>> l[0].print()
MyBase::print()
>>> l[1].print()
MyDerived::print()https://stackoverflow.com/questions/49633990
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