我有一个简单的实体:
@Entity
@Table(name = "dish_type")
class DishType : Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
var id: Long = -1
var name: String? = null
var description: String? = null
@OneToMany(mappedBy = "dishType")
var dishTypeLocales: List<DishTypeLocale>? = null
}
@Entity
@Table(name = "dish_type_locale")
class DishTypeLocale : Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
var id: Long = -1
@Enumerated(EnumType.STRING)
var locale: LocaleString? = null
var value: String? = null
@ManyToOne
@JoinColumn(name = "dish_type_id")
var dishType: DishType? = null
}DAO:
interface DishTypeService {
fun findAll(withLocale: Boolean): List<DishTypeDto>
}
@Service
@Transactional
open class DishTypeServiceImpl(private val dishTypeRepository: DishTypeRepository) : DishTypeService {
override fun findAll(withLocale: Boolean): List<DishTypeDto> {
return this.dishTypeRepository.findAll().map { DishTypeDto(it, withLocale) }
}
}
@Repository
interface DishTypeRepository : JpaRepository<DishType, Long>DTO:
class DishTypeDto {
var id: Long = -1
var description: String? = null
var locale: List<DefaultLocalizationDto>? = null
constructor()
constructor(dishType: DishType, withLocale: Boolean) {
this.id = dishType.id
this.description = dishType.description
if (withLocale) {
this.locale = dishType.dishTypeLocales?.map { DefaultLocalizationDto(it) }
}
}
override fun toString(): String {
return "DishTypeDto{" +
"id=" + id +
", description='" + description + '\'' +
'}'
}
}
class DefaultLocalizationDto {
var locale: Int? = null
var name: String? = null
var description: String? = null
constructor()
constructor(locale: DishTypeLocale) {
this.locale = locale.locale?.code
this.name = locale.value
}
override fun toString(): String = "DefaultLocalizationDto(locale=$locale, name=$name, description=$description)"
}对于DishTypeService.findAll(false),我们有1条语句给DB:
Session Metrics {
6789040 nanoseconds spent acquiring 1 JDBC connections;
0 nanoseconds spent releasing 0 JDBC connections;
146499 nanoseconds spent preparing 1 JDBC statements;
3929488 nanoseconds spent executing 1 JDBC statements;
0 nanoseconds spent executing 0 JDBC batches;
0 nanoseconds spent performing 0 L2C puts;
0 nanoseconds spent performing 0 L2C hits;
0 nanoseconds spent performing 0 L2C misses;
0 nanoseconds spent executing 0 flushes (flushing a total of 0 entities and 0 collections);
43774 nanoseconds spent executing 1 partial-flushes (flushing a total of 0 entities and 0 collections)
}对于DishTypeService.findAll(true)语句,== table.size (在我的例子中是282):
Session Metrics {
11570010 nanoseconds spent acquiring 1 JDBC connections;
0 nanoseconds spent releasing 0 JDBC connections;
4531164 nanoseconds spent preparing 282 JDBC statements;
60280410 nanoseconds spent executing 282 JDBC statements;
0 nanoseconds spent executing 0 JDBC batches;
0 nanoseconds spent performing 0 L2C puts;
0 nanoseconds spent performing 0 L2C hits;
0 nanoseconds spent performing 0 L2C misses;
0 nanoseconds spent executing 0 flushes (flushing a total of 0 entities and 0 collections);
60464 nanoseconds spent executing 1 partial-flushes (flushing a total of 0 entities and 0 collections)
}如何告诉Spring,获取1中的所有数据(ok mb2-3语句)?
@OneToMany(mappedBy = "dishType", fetch = FetchType.EAGER)
var dishTypeLocales: List<DishTypeLocale>? = null好心帮不上忙
我知道,我可以从dishTypeLocales中删除DishType,在两个单独的方法中得到所有的dishTypes然后是所有的dishTypeLocales,然后在代码中映射它们,但是mb有更好的方法吗?
我在用:
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.0.0.RELEASE</version>DB: Postgresql 9.6
发布于 2018-03-18 20:20:23
您正在经历关系的延迟加载,这是OneToMany关系的默认行为。
你在这里有四个选择:
FETCH JOIN加载实体以及关系。为此,您必须在存储库中使用以下查询(草稿)编写自定义方法:SELECT dt FROM DishType dt JOIN FETCH dt.dishTypeLocaleshttps://stackoverflow.com/questions/49351763
复制相似问题