如何解析Go中的RSA公钥？

Question

为什么我从以下代码中获得错误ssh: short read：

package main

import (
    "golang.org/x/crypto/ssh"
    "testing"
)

func TestPublicKeyParsing(t *testing.T) {
    key := "ssh-rsa AAAAB3NzaC1yc2EAAAADAQABAAABAQDhZgLqiZYDKCWhyi2gUXIRwIPyMSyXZ6yrwsm3PYfIvFB60kVlNgqDpPVhWoH6eRfaQ1y/xbg4nClZmHEDTvLbTQ1ZoQzzjZ7zvM6aQ4nADmKcCYswEuU94axouVjsHNyMLfOkPXuGec0fChwQ2JDh/B9LCiSDxyhCOgHvETXGXsyBMKjn498iPjJ6snzk35dy5wPZRz41g3dLaygF+wYAT791u/JchHQL7OP7RoNgby+RM16SYZs1tgQVkfU//o+AyTarWYLVDpFU6HPPenE4xEXhbgqd7x3wSNPBsMvY8Zjcu3kdHtboJidyMtKeD8ghV/T24kME58TW15T8Eg8R"

    _, err := ssh.ParsePublicKey([]byte(key))
    if err != nil {
        t.Errorf("ERROR! %s", err)
    }
}

键字符串是否格式错误？

公钥的正确格式是什么？

Answer 1

这看起来像authorized_keys格式，您可以用ssh.ParseAuthorizedKey解析它

package main

import (
    "golang.org/x/crypto/ssh"
    "testing"
)

func TestPublicKeyParsing(t *testing.T) {
    key := "ssh-rsa AAAAB3NzaC1yc2EAAAADAQABAAABAQDhZgLqiZYDKCWhyi2gUXIRwIPyMSyXZ6yrwsm3PYfIvFB60kVlNgqDpPVhWoH6eRfaQ1y/xbg4nClZmHEDTvLbTQ1ZoQzzjZ7zvM6aQ4nADmKcCYswEuU94axouVjsHNyMLfOkPXuGec0fChwQ2JDh/B9LCiSDxyhCOgHvETXGXsyBMKjn498iPjJ6snzk35dy5wPZRz41g3dLaygF+wYAT791u/JchHQL7OP7RoNgby+RM16SYZs1tgQVkfU//o+AyTarWYLVDpFU6HPPenE4xEXhbgqd7x3wSNPBsMvY8Zjcu3kdHtboJidyMtKeD8ghV/T24kME58TW15T8Eg8R"

    parsedKey, _, _, _, err := ssh.ParseAuthorizedKey([]byte(key))
    if err != nil {
        t.Errorf("ERROR! %s", err)
    }
}