Python :将ECEF的速度转换为J2000坐标系

Question

我编写了一个代码，将坐标从地球固定系统转换为惯性系，使用的是无粘滞：

from astropy import coordinates as coord
from astropy import units as u
from astropy.time import Time
from astropy import time

now = Time('2018-03-14 23:48:00')
# position of satellite in GCRS or J20000 ECI:
xyz=[-6340.40130292,3070.61774516,684.52263588]

cartrep = coord.CartesianRepresentation(*xyz, unit=u.km)
gcrs = coord.ITRS(cartrep, obstime=now)
itrs = gcrs.transform_to(coord.GCRS(obstime=now))
loc= coord.EarthLocation(*itrs.cartesian.xyz)
print(loc)

如何对速度也进行变换？

Answer 1

我认为你可以这样做：

from astropy import coordinates as coord
from astropy import units as u
from astropy.time import Time

now = Time('2018-03-14 23:48:00')

xyz = [-6340.40130292, 3070.61774516, 684.52263588]
vxvyvz = [-10.90, 56.4, -74.6]

# put velocities into cartesian differential
cartdiff = coord.CartesianDifferential(*vxvyvz, unit='km/s')
cartrep = coord.CartesianRepresentation(*xyz, unit=u.km, differentials=cartdiff)

gcrs = coord.ITRS(cartrep, obstime=now)
itrs = gcrs.transform_to(coord.GCRS(obstime=now))

# print position
print(itrs.cartesian.xyz)

# print velocity
print(itrs.cartesian.differentials)

但是，我不太确定它能不能满足你的要求。或者，在astropyv.3.0.1中，ITRS类似乎能够获取速度值，因此您可以使用

now = Time('2018-03-14 23:48:00')
pos = [-6340.40130292, 3070.61774516, 684.52263588]*u.km
vel = [-10.90, 56.4, -74.6]*u.km/u.s

gcrs = coord.ITRS(x=pos[0], y=pos[1], z=pos[2], v_x=vel[0], v_y=vel[1], v_z=vel[2], representation_type='cartesian', differential_type='cartesian', obstime=now)
itrs = gcrs.transform_to(coord.GCRS(obstime=now))

# print position
print(itrs.cartesian.xyz)

# print velocity
print(itrs.cartesian.differentials)

这两个版本都给出了相同的答案，但第二个版本的答案比较清晰。