Swift中具有特定属性的html标记的解析

Question

是否有一种方法可以解析具有特定属性的标记的HTML

现在，我使用以下代码获取页面的内容(使用SwiftSoup)：

    // Checking if MyLink is working
    guard let myURL = URL(string: MyLink) else {                                                 // myURL needed only temporarly
        print("Error: \(MyLink) doesn't seem to be a valid URL")
        return
    }

    // Getting all content of website for a specific link
    do {
        MyLinkContent = try String(contentsOf: myURL, encoding: .ascii)
    } catch let error {
        print("Error: \(error)")
    }

获得内容后，我可以将所有链接保存在数组中，例如使用以下代码：

        // Searching for all links in the content of the URL and creating elements
        guard let linkElements: Elements = try? SwiftSoup.parse(MyLinkContent).select("a")  else {return}
        //  Now all elements are printed into an array
        for element: Element in linkElements.array(){
            MyLinkArray.append("\(element)")
        }

这将导致一个包含网站所有链接的数组。

然而，我的问题是，比如说主页有很多标签，格式如下：

- Things I don't need especially a lot of <tr tags but with other attributes I don't need
- <tr id="row_">"TheContentINeed"</tr>
- <tr id="row_">"TheContentINeed"</tr> 
- <tr id="row_">"TheContentINeed"</tr> 
- <tr id="row_">"TheContentINeed"</tr> 
- <tr id="row_">"TheContentINeed"</tr> 
- More Things I don't need specially a lot of <tr tags but with other attributes I don't need

我希望将所有内容保存在数组中，但只保存属性为"id“的标记。

有什么想法吗？我更愿意再次使用SwiftSoup (如果可能的话)。谢谢!

Answer 1

组合你的CSS选择器。请参阅更多的示例项目。

// Searching for all links in the content of the URL and creating elements
guard let linkElements: Elements = try? SwiftSoup.parse(MyLinkContent).select("a tr[id="row"]")  else {return}
//  Now all elements are printed into an array
for element: Element in linkElements.array(){
   MyLinkArray.append("\(element)")
}