从电子邮件文本中提取日期和时间的Regex

Question

我有一份文件里面有很多文字。有些看起来是这样的：

X-DSPAM-Processed: Fri Jan  4 18:10:48 2008
X-DSPAM-Confidence: 0.6178
X-DSPAM-Probability: 0.0000

Details: http://source.sakaiproject.org/viewsvn/?view=rev&rev=39771

Author: louis@media.berkeley.edu
Date: 2008-01-04 18:08:50 -0500 (Fri, 04 Jan 2008)
New Revision: 39771

Modified:
bspace/site-manage/sakai_2-4-x/site-manage-tool/tool/src/bundle/sitesetupgeneric.properties
bspace/site-manage/sakai_2-4-x/site-manage-tool/tool/src/java/org/sakaiproject/site/tool/SiteAction.java
Log:
BSP-1415 New (Guest) user Notification

我只需要找出遵循这种模式的日期：

2008-01-04 18:08:50 -0500

以下是我尝试过的：

import re

text = open('mbox-short.txt')
for line in text:
    dates = re.compile('\d{4}(?P<sep>[-/])\d{2}(?P=sep)\d{2}\s\d{2}:\d{2}:]\d{2}\s[-/]\d{4}')
    print(dates)

text.close()

我得到的回报是：

\d{4}(?P<sep>[-/])\d{2}(?P=sep)\d{2}\s\d{2}:\d{2}:]\d{2}\s[-/]\d{4}

Answer 1

这是另一个解决办法。

import re
numberExtractRegex = re.compile(r'(\d\d\d\d[-]\d\d[-]\d\d\s\d\d[:]\d\d[:]\d\d\s[-]\d\d\d\d)')
print(numberExtractRegex.findall('Date: 2008-01-04 18:08:50 -0500 (Fri, 04 Jan 2008), Date: 2010-01-04 18:08:50 -0500 (Fri, 04 Jan 2010)'))