ArangoDB / AQL更新嵌套文档

Question

鉴于以下文件结构：

{
  "_key": "abc",
  "_id": "abc",
  "label": "Company ABC",
  "departments": [
    {
      "name": "Department 123",
      "id": "123"
    },
    {
      "name": "Department 456",
      "id": "456"
    }
  ]
}

你能告诉我为什么以下查询不起作用吗？错误信息是“缺少文档键”。我在另一个SO (ArangoDB AQL: Update single object in embedded array)中找到了一个更复杂的解决方案，但我很好奇简单查询到底有什么问题。

FOR c IN company
  FOR d in c.deparments
    FILTER d.id == “456”
    UPDATE d WITH { name: “Department 789” } IN company
RETURN d

Answer 1

目前，我只知道如何更新ArangoDB中的顶级属性。虽然我希望将来有一些替代方案提请我注意，但这里有一些供您选择的方案。

用合并更新

在本例中，我们通过重写数组并在条件被击中时使用MERGE函数更新顶级departments属性。

LET company = DOCUMENT("companies/abc")

UPDATE company WITH {
  departments:
   (FOR department IN company.departments
     RETURN department.id == "456" ?
       MERGE(department, {name: "Department 789"}) : department)
} IN companies

使用替代数据模型

以上示例假设部门数据嵌入到公司文档中。请考虑以下几点：

“公司”收藏

{
  "_key": "abc",
  "_id": "companies/abc",
  "label": "Company ABC"
}

“部门”集合(单独的文档)

{
  "_key": "456",
  "_id": "departments/456",
  "company": "companies/abc",
  "name": "Department 456"
}

{
  "_key": "123",
  "_id": "departments/123",
  "company": "companies/abc",
  "name": "Department 123"
}

获得公司#ABC与部门：

LET company = DOCUMENT("companies/abc")

LET departments =
  (FOR department IN departments
    FILTER department.company == company._id
    RETURN department)

RETURN MERGE(company, {departments})

结果：

{
  "_id": "companies/abc",
  "_key": "abc",
  "label": "Company ABC",
  "departments": [
    {
      "_key": "456",
      "_id": "departments/456",
      "company": "companies/abc",
      "name": "Department 456"
    },
    {
      "_key": "123",
      "_id": "departments/123",
      "company": "companies/abc",
      "name": "Department 123"
    }
  ]
}

更新部门#456:

LET department = DOCUMENT("departments/456")

UPDATE department WITH {name: "Department 789"} IN departments

请注意，您希望在company集合中对departments属性添加一个索引。您可以在这里获得有关索引的详细信息：

https://docs.arangodb.com/3.3/Manual/Indexing/WhichIndex.html

你必须权衡这两种模式的利弊。