我有一个名为" new“的表,我想将ManufactureDate中的年份提取到一个新的列”年份“中。
新美元制造商:
2014-01-01
2016-01-01
2005-01-01
1997-11-01创建一个新列," new“如下所示:
ManufactureDate year
2014-01-01 2014
2016-01-01 2016
2005-01-01 2005
1997-11-01 1997我的代码:
for (i in 1:nrow(new)){
new["year"] <- NA
new$year[i] <- strsplit(new$ManufactureDate, "-")[[i]][1]
print(new$year[i])
}结果:打印成功,但当我检查表格“新”时,它显示如下,不确定发生了什么:
ManufactureDate year
2014-01-01 NA
2016-01-01 NA
2005-01-01 NA
1997-11-01 1997发布于 2018-02-23 02:04:09
实际上,我将投票反对创建“年度”专栏。如果使用的是实际日期列,则应从该现有列中提取年份,而不是取消数据或创建虚拟年份列。
df <- data.frame(ManufactureDate=as.Date(c("2014-01-01", "2016-01-01",
"2005-01-01", "1997-11-01")))
format(df$ManufactureDate, "%Y")
[1] "2014" "2016" "2005" "1997"发布于 2018-02-23 02:03:38
不需要for循环。除了到目前为止已经尝试过的(使用strsplit)之外,还有一种可能性:
new$year <- sapply(strsplit(as.character(new$ManufactureDate), "-"), "[[", 1);
# ManufactureDate year
#1 2014-01-01 2014
#2 2016-01-01 2016
#3 2005-01-01 2005
#4 1997-11-01 1997样本数据
new <- read.table(text =
"ManufactureDate
2014-01-01
2016-01-01
2005-01-01
1997-11-01", header = T)https://stackoverflow.com/questions/48940026
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