反应-本机与mobx抛出错误

Question

我用mobx实现了本机的react，我得到了这个错误。

mobx遇到了一个由反应或观察者组件引发的不明确的异常，在：'ReactionReaction@1错误:序列化未能找到未定义的默认模式

根成分

    import React, { Component } from 'react';
import {
    View,
    AsyncStorage,
    Text,
} from 'react-native';
import { StackNavigator } from 'react-navigation';

import { observer, Provider } from 'mobx-react/native'
import { create } from 'mobx-persist'
import { AppStore,UserStore } from '../stores'
const stores = { UserStore, AppStore };

import {
    Walkthrough
} from '../screens'

const hydrate = create({
    storage: AsyncStorage
})

let Main = null;

hydrate('appStore', AppStore).then((a) => {
    console.log(a);
    AppStore.done();   
    }
)

hydrate('userStore',UserStore).then((a)=>{
    console.log(a)
    Main = StackNavigator(
        {
            Walkthrough: { screen: Walkthrough },

        }, {
            headerMode: 'none',
            lazy: true,
            initialRouteName: 'Walkthrough',
        }
    )
})



@observer
class Root extends Component {
    constructor(props){
        super(props);
        this.state = {

        }
    }


    render(){
        // const ready =  UserStore.storeHydrated &&  AppStore.storeHydrated;
        const ready = false;
        return (
            <View>
            {!ready &&  
                <View><Text>Splash screen component</Text></View>}

            </View>

        )  
    }
}

export default Root;

AppStore

    import { observable, action, computed } from 'mobx'
import { persist } from 'mobx-persist'

class AppStore {
    @observable storeHydrated = false
    @observable requesting = false

    constructor(){
        console.log("AppStore")
    }

    @action setRequesting(){
        this.requesting = !this.requesting;
    }

    @action done(){
        //this.storeHydrated = true
    }


}


const appStore = new AppStore();
export default appStore;

UserStore

    import { observable, action, computed } from 'mobx'
import { persist } from 'mobx-persist'

class UserStore {
    @persist @observable first_name;
    @persist @observable last_name;
    @persist @observable email;
    @persist @observable tasks;
    @persist @observable storeHydrated = false;
    @persist @observable alreadyRegister = false;

    constructor(){
        this.setUser = this.setUser.bind(this);
        console.log("userStore")
    }

    @action setUser(data){
        this.first_name = data.first_name
        this.last_name = data.last_name;
        this.email = data.email;
        this.tasks = data.tasks;
    }

    @action done(){
        //this.storeHydrated = true;
        // if(this.alreadyRegister){
        //     this.getUserDetails();
        // }
    }

    @action setIsFirstTimeInApp(firstTIme){
        this.firstTimeInApp = firstTIme;
    }


}


const user = new UserStore();
export default user;

我已经尝试做的是删除应用程序，并再次运行，但仍然没有什么改变，它抛给我同样的错误。

Answer 1

问题是

@persist @observable storeHydrated = false;

在UserStore内部不应该持久化，因为它是在应用程序的每个负载上重新启动的值。

因为它是持久化的，所以true的值在第一次运行后保存在存储中。

因此，请使用：

@observable storeHydrated = false;

然后，在定义StackNavigator之前，呈现Main。

额外小费：

在使用@persist @observable varName时，您应该始终初始化一个值，甚至是null，因为没有正确地支持“未定义”的序列化，因此它应该如下所示：@persist @observable varName = null (或任何适合于空字符串、0、true、false等的东西)。至于特别计划，则应：

@persist('list') @observable varName = [] 
@persist('object') @observable varName = null
@persist('map') @observable varName = new Map()