如何在java中的JCR节点上迭代？

Question

我在Adobe6.2中有一个用于滑块的touch-ui multi-field component，我无法在保存在JCR中的多个节点上迭代，在遍历每个需要创建数组列表以在HTL中进一步使用的节点之后。

JCR节点如下所示

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JAVA逻辑代码1：

public class SliderLogic extends WCMUse {
    private ValueMap childProperties;
    private Integer childCount;

    @Override
    public void activate() throws Exception {

        String childNode = get("childNode", String.class);
        Resource childResource = getResource().getChild(childNode);

        System.out.println("childResource++++" + childResource);
        if (childResource != null) {

            childProperties                     = childResource.adaptTo(ValueMap.class);

            for(Entry<String, Object> e : childProperties.entrySet()) {
                String key = e.getKey();
                Object value = e.getValue();
                System.out.println("Elements=" + e);
                System.out.println("key=" + key);
                System.out.println("value=" + value);
            }


        }
    }


    public ValueMap getChildProperties() {

        return childProperties;
    }
}

代码1的系统输出如下：

childResource++++JcrNodeResource, type=nt:unstructured, superType=null, path=/content/zero-6/en/jcr:content/content-parsys/slider/slides
Elements=jcr:primaryType=nt:unstructured
key=jcr:primaryType
value=nt:unstructured

Code2:又一次尝试，但没有运气

@Override
public void activate() throws Exception {

    String childNode = get("childNode", String.class);
    Resource childResource = getResource().getChild(childNode);

    System.out.println("childResource++++" + childResource);
    if (childResource != null) {

        childProperties                     = childResource.adaptTo(ValueMap.class);
        Iterable<Resource> getChildren      = getResource().getChildren();
        Iterator<Resource> children         = getResource().listChildren();

        System.out.println("childProperties="+childProperties);
        System.out.println("getChildren="+getChildren);

        while (children.hasNext()) {

            Resource child = children.next();
            System.out.println("child=" + child);

        }


    }
}

用于代码2的系统：

childResource++++JcrNodeResource, type=nt:unstructured, superType=null, path=/content/zero-6/en/jcr:content/content-parsys/slider/slides
childProperties=JcrPropertyMap [node=Node[NodeDelegate{tree=/content/zero-6/en/jcr:content/content-parsys/slider/slides: { jcr:primaryType = nt:unstructured, 1 = { ... }, 2 = { ... }, 3 = { ... }, 4 = { ... }}}], values={jcr:primaryType=nt:unstructured}]
getChildren=org.apache.sling.api.resource.AbstractResource$1@34488dc4
child=JcrNodeResource, type=nt:unstructured, superType=null, path=/content/zero-6/en/jcr:content/content-parsys/slider/bannerImage
child=JcrNodeResource, type=nt:unstructured, superType=null, path=/content/zero-6/en/jcr:content/content-parsys/slider/slides

用于呈现的HTL代码

<div data-sly-use.slide="${'SliderLogic' @ childNode='slides'}">

        <ul data-sly-list.child="${resource.listChildren}">
            <li>${child} ==  ${child.slideTitle || 'no title'} </li>
        </ul>
</div>

Answer 1

假设呈现的资源对应于slider/slides，则可以使用以下HTL片段：

<ul data-sly-list.child="${resource.listChildren}">
    <li>${child.properties.slideTitle || 'no title'}</li>
</ul>

如果呈现的资源与此不对应，则可以利用use对象返回slides资源或直接将其子节点作为列表/迭代器返回。