for构建删除/销毁-为构建规范创建无构建

Question

在我们的构建定义中还保留了1000多个版本，不管保留设置如何:我想用脚本删除构建，我正在尝试从远程PC上运行。我们的tfs服务器是2015.2。

tfsbuild destroy /collection:http://tfsserver:8080/tfs/ProjectCollection /dateRange:01/01/2017~31/12/2017 /buildDefinition:teamProject\Builddefintion

输出显示：没有为构建规范找到构建。尽管有许多构建符合标准。任何帮助都是非常感谢的。谢谢!

Answer 1

Tfsbuild delete/destroy只适用于Xaml构建。首先需要delete，然后是destroy。

对于vNext构建，可以尝试使用REST (删除生成)删除它们：

DELETE http://server:8080/tfs/DefaultCollection/ProjectName/_apis/build/builds/{build Id}?api-version=2.0

您可以使用下面的PowerShell脚本删除2017年为特定构建定义所完成的所有构建：

Param(
   [string]$collectionurl = "http://server:8080/tfs/Collection",
   [string]$projectName = "ProjectName",
   [string]$builddefinitionID = "56",
   [string]$keepForever = "true",
   [string]$user = "username",
   [string]$token = "password"
)

# Base64-encodes the Personal Access Token (PAT) appropriately
$base64AuthInfo = [Convert]::ToBase64String([Text.Encoding]::ASCII.GetBytes(("{0}:{1}" -f $user,$token)))

#Get builds list which completed in the year 2017
$buildsUrl = "$($collectionurl)/$projectName/_apis/build/builds?definitions=$builddefinitionID&statusFilter=completed&api-version=2.0"   
$builds = (Invoke-RestMethod -Uri $buildsUrl -Method Get -Headers @{Authorization=("Basic {0}" -f $base64AuthInfo)}).value | where({$_.finishTime -like '*2017*'})

#Delete the builds 
foreach ($build in $builds.id)
{
$deleteurl = "$($collectionurl)/$projectName/_apis/build/builds/$build"+"?api-version=2.0"

$result = (Invoke-RestMethod -Uri $deleteurl -Method Delete -Headers @{Authorization=("Basic {0}" -f $base64AuthInfo)})

Write-Host "Builds deleted with the ID" : $build 
}