我把Waze集成到我的Swift应用程序中,但是当我点击按钮时,Waze打开了,但是导航没有什么变化。我只是看到了应用程序,仅此而已,而不是启动导航。
以下是代码:
@IBAction func openWazeAction(_ sender: Any) {
// open waze
if UIApplication.shared.canOpenURL(URL(string: "waze://")!) {
let urlStr = String(format: "waze://ul?ll=%f,%f&navigate=yes", (selectedBorne?.location?.x)!, (selectedBorne?.location?.y)!)
print(urlStr)
UIApplication.shared.open(URL(string: urlStr)!)
} else {
UIApplication.shared.open(URL(string: "http://itunes.apple.com/us/app/id323229106")!)
}
}print(urlStr)返回正确的URL:waze://ul?ll=48.792914,2.366290&navigate=yes,但是在Waze应用程序中什么也不会发生。
(我将LSApplicationQueriesSchemes放在Info.plist文件中。)
这里怎么了?
发布于 2018-02-09 10:10:50
我解决了问题。Waze文件给出了错误的信息,因为他们的iOS示例没有按应有的方式打开Waze应用程序。它在移动上打开Safari,然后我们需要点击一个链接来打开Waze。
正确的链接是:
waze://?ll={latitude},{longitude}&navigate=yes我需要删除URL中的ul。
斯威夫特
func navigateTo(latitude: Double, longitude: Double) {
if UIApplication.shared.canOpenURL(URL(string: "waze://")!) {
// Waze is installed. Launch Waze and start navigation
let urlStr = String(format: "waze://?ll=%f,%f&navigate=yes", latitude, longitude)
UIApplication.shared.open(URL(string: urlStr)!)
} else {
// Waze is not installed. Launch AppStore to install Waze app
UIApplication.shared.open(URL(string: "http://itunes.apple.com/us/app/id323229106")!)
}
}Objective-C
(void) navigateToLatitude:(double)latitude longitude:(double)longitude
{
if ([[UIApplication sharedApplication]
canOpenURL:[NSURL URLWithString:@"waze://"]]) {
// Waze is installed. Launch Waze and start navigation
NSString *urlStr =
[NSString stringWithFormat:@"waze://?ll=%f,%f&navigate=yes",
latitude, longitude];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlStr]];
} else {
// Waze is not installed. Launch AppStore to install Waze app
[[UIApplication sharedApplication] openURL:[NSURL
URLWithString:@"http://itunes.apple.com/us/app/id323229106"]];
}
}发布于 2020-11-28 04:53:45
选择的答案对我不起作用,我在设备上运行这个应用程序,安装了waze,它总是打开appstore。使用此代码,如果安装了waze,则打开waze;如果没有,则打开appstore。
let urlStr = String(format: "waze://?ll=%f,%f&navigate=yes", latitude, longitude)
UIApplication.shared.open(URL(string: urlStr)!) { didOpen in
if !didOpen {
UIApplication.shared.open(URL(string: "http://itunes.apple.com/us/app/id323229106")!)
}
}https://stackoverflow.com/questions/48660902
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