在表单的“编辑视图”中,我有一个复选框列表,我想检查表book_have_languages中的复选框(请注意,一本书可以有多种语言)。
代码:
<?php $query_c = mysqli_query($mysqli, "SELECT id_language, name_language FROM languages ORDER BY name_language;")
or die('error '.mysqli_error($mysqli));
while ($data_c = mysqli_fetch_assoc($query_c)) {
echo "<div class='checkbox'><label><input type='checkbox' name='languages[]' value='$data_c[id_languages]'>$data_c[name_language]</label></div>";
$sql = "SELECT id_book, id_language FROM book_have_languages WHERE id_book=3";
$res = $mysqli->query($sql) or die("error: ".$sql);
$results = array();
while($row = mysqli_fetch_assoc($res)) {
$results[] = $row;
}
foreach ($results as $result){
if($result['id_language'] == $data_c['id_language']){
echo"<div class='checkbox'><label><input type='checkbox' name='languages[]' value='$data_c[id_language]'checked >$data_c[name_language]</label></div>";
}
}
}
?>结果:
如果我的桌子是:
id_book x- id_language
3-2
3-5
3-6
检查语言2、5、6,但它们看起来是重复的。如何在第一个回显中只显示表中没有的语言?
发布于 2018-02-05 19:53:59
你在浏览各种语言,而不是通过一本书所拥有的语言。如果您的表如所描述的那样,$data_idi应该有多个结果,并且只匹配第一个结果。您也应该在这些结果中循环。
发布于 2018-02-06 13:35:41
我就是这样解决的:
<?php
$query_c = mysqli_query($mysqli, "SELECT id_language, name_language FROM languages ORDER BY name_language;")
or die('error '.mysqli_error($mysqli));
while ($data_c = mysqli_fetch_assoc($query_c)) {
$sql = "SELECT id_book, id_language FROM book_te_languages WHERE id_book='$_GET[id]'";
$res = $mysqli->query($sql) or die("error: ".$sql);
$results = array();
while($row = mysqli_fetch_assoc($res)) {
$results[] = $row;
}
echo "<div class='checkbox'><label><input type='checkbox' name='languages[]' value='$data_c[id_language]'";
foreach ($results as $result){
if($result['id_language'] == $data_c['id_language']){
echo "checked";
}
}
echo ">$data_c[name_language]</label></div>";
}
?>https://stackoverflow.com/questions/48629852
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