简化PyreResponse迭代

Question

这是我的密码：

lastRow = db.child("twitter-search").order_by_key().limit_to_last(1).get(user['idToken'])

latestId = None

for row in lastRow.each():
for key, value in row.val().items():
    if key == "latest_id":
        latestId = value

它正在起作用，但是否有办法使它更短？

Answer 1

若要检查密钥是否存在，请O(1)更新latestId。

latestId = None
for row in lastRow.each():
    if "latest_id" in row:
        latestId = row["latest_id"]