是否可以在R中创建一元运算符?我知道创建这样的二进制运算符是可能的:
setGeneric("%power%", function(x, y) x ^ y)
2 %power% 4但是是否有可能创建像-这样的一元运算符。我试过这样的方法:
setGeneric("%-%", function(x) -x)
%-% 3但这不管用
发布于 2018-01-11 13:58:34
R解析器不支持自定义一元运算符。
来自R语言定义的受支持运算符列表的副本
- Minus, can be unary or binary
+ Plus, can be unary or binary
! Unary not
~ Tilde, used for model formulae, can be either unary or binary
? Help
: Sequence, binary (in model formulae: interaction)
* Multiplication, binary
/ Division, binary
^ Exponentiation, binary
%x% Special binary operators, x can be replaced by any valid name
%% Modulus, binary
%/% Integer divide, binary
%*% Matrix product, binary
%o% Outer product, binary
%x% Kronecker product, binary
%in% Matching operator, binary (in model formulae: nesting)
< Less than, binary
> Greater than, binary
== Equal to, binary
>= Greater than or equal to, binary
<= Less than or equal to, binary
& And, binary, vectorized
&& And, binary, not vectorized
| Or, binary, vectorized
|| Or, binary, not vectorized
<- Left assignment, binary
-> Right assignment, binary
$ List subset, binary(解析器还支持二进制操作符:=,这里没有记录这个操作符,因为它不为基R所用)
请注意,惟一的自定义运算符("%x%特殊二进制运算符,x可以被任何有效名称替换“)是二进制。
因此,您唯一的选择是重载现有的一元操作符,分别为其编写一个方法。
发布于 2021-03-04 01:23:27
虽然我不熟悉setGeneric,但我可以回答这个问题
是否可以在R中创建一元运算符?
是的,算是吧,但不是真的。你可以假装:
# LET'S USE A BINARY OPERATOR TO DEFINE A UNARY OPERATOR:
# THE SYMBOL /*/<- IS SUPPOSED TO LOOK LIKE PERCENT-WILDCARD-PERCENT--ASSIGNMENT-ARROW
`%/*/<-%` <- function ( name , FUN , safe = TRUE ) {
`%//%` <- paste0
NAME <- "%" %//% name %//% "%"
PARENT <- parent.frame ()
if ( safe && exists ( NAME , PARENT ) )
stop ( NAME %//% " exists." )
assign (
x = NAME ,
value = function ( x , ignored ) FUN ( x ) ,
envir = PARENT ) }
.. <- NULL # THIS IS WHAT I MEAN BY FAKING IT...
"-" %/*/<-% `-` # ... `%-%` IS ACTUALLY A BINARY OPERATOR....
1 %-%.. # ... IN THIS CALL, `..` IS THE SECOND ARGUMENT.
# [1] -1
1 %-%.. %-%..
# [1] 1
"t" %/*/<-% `t`
m <- matrix(1:4, 2)
m
# [,1] [,2]
# [1,] 1 3
# [2,] 2 4
m %t%..
# [,1] [,2]
# [1,] 1 2
# [2,] 3 4
"-" %/*/<-% `-`
# Error in "-" %/*/<-% `-` : %-% exists.
i <- floor ( runif ( 9 , min = 1 , max = 10 ) )
i
# [1] 2 3 2 1 7 3 9 5 9
unique(i)
# [1] 2 3 1 7 9 5
"u" %/*/<-% function ( x ) sort ( unique ( x ) )
i %u%..
# [1] 1 2 3 5 7 9https://stackoverflow.com/questions/48208590
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