我试图解析下面的json,并在第150行(在代码中标记)捕捉到JSONException,我无法弄清楚为什么会发生这种情况。目标是查找特定包的测试列表,并将其存储在arraylist中。
当我将screen_package作为第二次争论传递时,日志消息是:值screen_package类型的java.lang.String不能转换为JSONObject。根据我的理解,我们可以在String的构造函数中传递JSONObject对象。如果我错了,请纠正我。看一看
{
"package_name": {
"camera_package": {
"RearCamera": {
"test_name": "RearCamera",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "RearCamera",
"test_category": "manual",
"order": "42"
},
"FrontCamera": {
"test_name": "FrontCamera",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "FrontCamera",
"test_category": "manual",
"order": "43"
},
"Flash": {
"test_name": "Flash",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "Flash",
"test_category": "manual",
"order": "1"
},
"AutoFocus": {
"test_name": "AutoFocus",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "AutoFocus",
"test_category": "manual",
"order": "35"
},
"VideoRecord": {
"test_name": "VideoRecord",
"test_type": "mandatory",
"visibility": "true",
"report_name": "VideoRecord",
"test_category": "manual",
"order": "10"
},
"FrontVideoRecorder": {
"test_name": "FrontVideoRecorder",
"test_type": "mandatory",
"visibility": "true",
"report_name": "FrontVideoRecorder",
"test_category": "manual",
"order": "11"
}
},
"screen_package": {
"Screen": {
"test_name": "Screen",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "Screen",
"test_category": "manual",
"order": "21"
}
}
}
}以下是java代码:
public void parseJSON(String jsonName, String packageName) {
try {
JSONObject jsonRootObject = new JSONObject(jsonName);
if (jsonRootObject != null && jsonRootObject.length() > 0) {
Iterator<String> packageKeys = jsonRootObject.keys();
if (packageKeys != null) {
while(packageKeys.hasNext()){
String currentPackageKey = packageKeys.next();
if(currentPackageKey!= null && currentPackageKey.length()>0 &&
currentPackageKey.equals(packageName)){
JSONObject jsonPackageObject = new JSONObject(currentPackageKey); //line 150
if(jsonPackageObject!=null && jsonPackageObject.length()>0) {
Iterator<String> testNameKeys = jsonPackageObject.keys();
if(testNameKeys!=null){
while(testNameKeys.hasNext()) {
String currentTestNameKey = testNameKeys.next();
if(currentTestNameKey!=null && currentTestNameKey.length()>0) {
//do something
}
}
}
}
}
}
}
}
} catch (JSONException e) {
e.printStackTrace();
System.out.println("Exception caught : "+e.getLocalizedMessage());
}
}发布于 2018-01-10 12:04:36
JSONException表示在JSON处理期间发生了一些异常。
您应该使用getJSONObject(String name)。
JSONObject getJSONObject (String name)如果存在且是JSONObject,则返回按名称映射的值,否则抛出
码结构
JSONObject screen_package = jsonobject.getJSONObject("screen_package"); 发布于 2018-01-10 12:03:06
在这里
JSONObject jsonPackageObject = new JSONObject(currentPackageKey);currentPackageKey是String.You必须提供JSON格式字符串的键。
所以把它换成
JSONObject jsonPackageObject = jsonRootObject.getJSONObject(currentPackageKey);https://stackoverflow.com/questions/48186971
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