我想编写我自己的JavaEE。我使用Linux和Glassfish 4作为App。我的Eclipse是氧气(EE-版本)。
我想检查一下我的顾客是否能登记。
我还没有包括CSS,所以它看起来可能有点无聊。:D
这些是我在Eclipse中的项目:

这是我的索引-HTML:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8"/>
<link rel="stylesheet" href="css/styles.css">
<title>Onlineshop</title>
</head>
<body>
<header>
<hgroup>
<h1 class="title">Onlineshop</h1>
</hgroup>
<nav>
<a href="index.html">Home</a>
<a href="register.html">Registrieren</a>
<a href="signin.html">Einloggen</a>
<a href="sell.html">Verkaufen</a>
<a href="search.html">Suchen</a>
</nav>
</header>
<footer>
Copyright
</footer>
</body>
"Registrieren“的意思是”注册“,"Einloggen”的意思是“登录”,"Verkaufen“的意思是”出售“,"Suchen”的意思是“搜索”。
这是在单击“Registrieren”之后显示的HTML站点:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8"/>
<link rel="stylesheet" href="css/styles.css">
<title>Onlineshop</title>
</head>
<body>
<header>
<hgroup>
<h1 class="title">Onlineshop</h1>
</hgroup>
<nav>
<a href="index.html">Home</a>
<a href="register.html">Registrieren</a>
<a href="signin.html">Einloggen</a>
<a href="sell.html">Verkaufen</a>
<a href="search.html">Suchen</a>
</nav>
</header>
<form action="register" method="post">
<fieldset>
<legend>Registrieren</legend>
<table>
<tbody>
<tr>
<th>
<label for="email">Email:</label>
</th>
<td>
<input
type="email"
name="email"
size="40"
maxlength="40"
title="muster@beispiel.de"
placeholder="E-Mail eingeben"
pattern=".{6,40}"
required="required">
</td>
</tr>
<tr>
<th>
<label for="password">
Password:
</label>
</th>
<td>
<input
type="password"
name="password"
size="10"
maxlength="10"
title="6-10 Zeichen"
placeholder=
"Passwort eingeben"
pattern=".{6,10}"
required="required">
</td>
</tr>
<tr>
<td/><td>
<input type="submit">
<input type="reset">
</td>
</tr>
</tbody>
</table>
</fieldset>
</form>
<footer>
Copyright
</footer>
</body>
这是我的Servlet:
package de.java2enterprise.onlineshop;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/register")
public class RegisterServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* Default constructor.
*/
public RegisterServlet() {
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse
response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse
response)
throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
final String email = request.getParameter("email");
final String password = request.getParameter("password");
final PrintWriter out = response.getWriter();
out.println("<!DOCTYPE html>");
out.println("<html>");
out.println("<body>");
out.println("<br> Ihre Eingaben");
out.println("<br> EMail: " + email);
out.println("<br> EMail: " + password);
out.println("</body>");
out.println("</html>");
}
}我没有编写Web.xml,因为我只想处理注释。现在我有两个问题:
Servlet的所有导入都无法解决。但是为什么呢?我确实创建了一个,并将Webproject war分配给了应用程序。玻璃鱼被分配给,在Glassfish-Server上记录了Servlet,不是吗?
第二个问题是:为什么在输入EMail和在寄存器上输入密码之后,他不能在点击submit之后找到Servlet呢?是否与问题1有关?
非常感谢!
发布于 2018-01-07 18:35:52
第一个问题-
Servlet的所有导入都无法解决。但是为什么呢?我确实创建了一个,并将Webproject war分配给了应用程序。玻璃鱼被分配给,在Glassfish-Server上记录了Servlet,不是吗?
我将eclipse与Java-8和Tomcat 8.5 web container结合使用,通过查看您的问题,我在eclipse中创建了一个新的dynamic web project,随后在您定义的包中创建了两个html文件index.html和register.html以及Servlet class RegisterServlet。
做完所有的工作后,--我只是首先启动并停止了我的web容器服务器,然后创建了一个Right click on the project name, Go to menu Run As > Run on Server > Choose an existing server, there I choose the Tomcat 8.5 Server at localhost > Remove all other projects from list Configured instead the current one and pressed the Finish。
前面我已经选择了,我已经选择了默认浏览器的步骤选项Window(Menu)>Web Browser>Chrome。
在我的项目中的WebContent/WEB/目录中没有这样的web.xml配置文件。
因此,Tomcat 8.5 server将在chrome新选项卡中启动和显示index.html页面,出现Optionshop page,我选择了Registrieren链接,然后重定向到register.html,然后在那里插入电子邮件id和密码,然后按Enter键,servlet mapping在新页面中查看我的电子邮件id和密码,就是这样。
第二个问题-
为什么他在输入EMail并在寄存器上输入密码后单击submit就找不到Servlet了?是否与问题1有关?
我将@WebServlet更改为/RegisterServlet,在register.html中将表单开始标记替换为
<form name="register" method="POST" action="RegisterServlet">在Servlet类中,方法doGet(HttpServletRequest request, HttpServletResponse response)也丢失了,因此我创建了一个方法,并且我的Servlet类如下所示:
package de.java2enterprise.onlineshop;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/RegisterServlet")
public class RegisterServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public RegisterServlet() { }
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException { }
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");
final String email = request.getParameter("email");
final String password = request.getParameter("password");
final PrintWriter out = response.getWriter();
out.println("<!DOCTYPE html>");
out.println("<html>");
out.println("<body>");
out.println("<br> Ihre Eingaben");
out.println("<br> EMail: " + email);
out.println("<br> EMail: " + password);
out.println("</body>");
out.println("</html>");
out.close();
}
}希望这能帮到你,谢谢。
https://stackoverflow.com/questions/48139947
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