骰子模拟发现正确的点

Question

你想要几个骰子点？ 6 试1:2 试2:4 试3:5 试4:6 在4次尝试中，你发现了6点

所以，这就是我试图得到的输出，但似乎找不到方法。

System.out.println("how many dice dots do u want?");
int dots = s.nextInt();
int dots2 = (int) (6 * Math.random()) + 1;

这就是我所拥有的。我现在试了一个for循环，但它似乎不起作用。有人能帮我吗？

Answer 1

你可以用这样的方式实现你想要的：

Scanner scan = new Scanner (System.in);

    int randomValue = 0;   //this is the random value that'd be autogenerated in each loop
    int counter = 1;    //this represents the number of trials

    System.out.println("how many dice dots do u want?");
    int dotsWanted = scan.nextInt();

    while(randomValue != dotsWanted){
        randomValue = (int) (6 * Math.random()) + 1;
        counter++;
    }

    System.out.printf("In %d trials, %d dots were found\n", counter, dotsWanted);

希望这能帮上忙..。快乐的编码！

Answer 2

请下次把你的问题写好，这有助于我们帮助你:)

你需要一个dice循环来掷骰子。

int dots = s.nextInt();
boolean found = false;
Random rnd = new Random();
while(!found) {
   int rolled= rnd.nextInt(6) + 1;
   if(rolled == dots) // do your stuff
        found = true;
}

希望能帮上忙。