我正在使用javascript中的websockets连接到一个API并读取一些数据。
以下是代码:
function processHUOBIAPI(client,exchange_name,exchange_wss,exchange_symbol)
{
// Define constants
const WebSocket = require('ws');
const pako = require('pako');
// Open connection once one is established
var wss = new WebSocket(exchange_wss);
wss.onopen = () =>
{
// Send request to subscribe
var symbol = exchange_symbol.toLowerCase()
wss.send(JSON.stringify(
{
"sub": "market." + symbol + ".kline.1min",
"id": symbol
}
));
};
// Parse channel information and send to Redis
wss.onmessage = (data) =>
{
//typedef data;
console.log("Receive message", data);
let text = pako.inflate(data, {
to: 'string'
});
mssg = JSON.parse(text);
if (mssg.ping) {
wss.send(JSON.stringify({
pong: mssg.ping
}));
} else if (mssg.tick) {
console.log(mssg);
//handle(msg);
} else {
console.log(text);
}
}
在这种情况下,我得到了一个错误:
./node_modules/pako/lib/通货膨胀. if :384 if (inflator.err) {抛出inflator.msg \ msginflator.err;}^未知压缩方法
如果我将"wss.onmessage = (data) =>"改为"wss.on“('message',(data) => {"并移除额外的')‘,代码工作得很好。
wss.on和wss.onmessage有什么区别?
这位新手非常感谢你的指导。如果这是个愚蠢的道歉.
发布于 2017-12-31 20:33:04
库WS是WebSocket API的包装器,因此"onmessage“在这里不能工作。
https://stackoverflow.com/questions/48044294
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